x^2 - 7x + 6 the y intercept occurs at (0, 6)
To find the x intercepts, set the function to 0 and factor, so we have....
x^2 - 7x + 6 = 0
(x - 6) (x - 1) = 0 and setting each factor to 0, the x intercepts occur at x = 6 and x = 1, i.e., at (6, 0) and (1, 0)
The turning point occurs at the vertex whose x coordinate is given by -[-7 ] / [ 2(1)] = 7/2 = 3.5
And the y coordinate of the vertex is : (7/2)^2 - 7(7/2) + 6 = - 49/4 + 24/4 = -25/4 = -6.25
Here's the graph........https://www.desmos.com/calculator/a0qnjcwsnh
