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I think Sisyphus still has my silver bullets.......that lunkhead....!!!!......it may be awhile before I get them back......he's still on the search for that Roman Zero.......remember???

You haven't given him any silver bullets have you Chris?  ...

Is your sister an albino?

Perhaps wer have similar taste in music too.

https://www.youtube.com/watch?v=SPtqRjirC6o

Maybe she will like it.

Yes....Melody also avoids crosses, wooden stakes and garlic, etc.......!!!!!

However.....here's a vampire slaying kit....if you need it.....

Can't tolerate the Sun?. Don't feel bad, because you have company in my sister, who is just like you. Surprise!. Have a good day.

Hi curious admirer,

Well it is 4:39am in Sydney right now.  This is a good time for me.

 If I allow direct sunlight to touch my skin I will burst into flames.  So this is a safe time :))

If you need to do it "by hand", follow the instructions in your text book.

If you need help with those instructions, post back and we will help you.

If you can use an on-line calculator, I suggest:  https://www.easycalculation.com/statistics/standard-deviation.php

Good luck!

Go to this link and they have a calculator that does what you want. You can play with it:

https://www.easycalculation.com/statistics/standard-deviation.php

23 is  relatively prime to the other two numbers..... thus, they have no GCF  [other than 1, of course ].....I have a feeling that you want to know what the LCM  - least common multiple is for these three numbers.......here's an easy way to do this.....

Factor these and put "like" factors in the same columns

23  =   23

24 =          2*3     *  3

78 =          2        *  3     *   13

Now......from each column, we want to select the factor with the higest power......if two or more factors have the same power, just select one of the factors

So we have

23, 2^3, 3, 13

Multiply all these together...... = 7176.......and this is the LCM

What is the G.C.F OF 24, 23,78 

The GCF of: 24, 23, 78 is 1. Why? Because 23 is a Prime number, which means it has no common factors with the other two.

f(x) =3 sec x

f ' (x)  = 3sec( x ) tan (x)

f '' (x)   = 3[ sec (x) tan (x) * tan (x)  + sec (x) * sec² (x)]

So

f " (pi/ 5)  = 3 [sec (pi/5) *  tan² (pi/5)  +  sec³ (pi/5 ]) =  about 7.623

Ok......post your problems and we'll see what we can do....

Do you mean

Find the second derivative of  3sec(pi/5)   ??

That is easy.  It is 0.  That is becasue there is no variable.   3sec(pi/5) is just a constant so the derivative is 0.

Hi Rosala,

I am glad you are back :))

That is a really nice post too :)

I think I like the last "Guest's" answer the best.......this explanation is very clear.......5 points from me.....!!!

....another way.....

you should know that log 100 = 2      right?

Well log 1000  =  3     right?

and log 10000 = 4      yah?

well 2460 is between   1000 and 10,000   right?    So log 2460 must be between  3 and 4 !

The two integers are 3 and 4......

In exponential form.....your  log equation is  10^x = 2460

Note

10³ = 1000

And

10⁴ = 10000

So

3 < log₁₀2460 < 4

Well, obviously, if x = log2460 just figure out what log 2460   IS !

log 2460 = 3.39      So 'x' is between  3   and   4

y=log5X and Y=5x

These are inverse graphs........and inverse graphs have "reversed" coordinates.....

So, just plots some points for y = 5^x    and then,  reverse the coordinates!!!.......this will give you the log graph...

For instance, when x = 1   5¹  = 5....so the point (1, 5)  is on the exponential graph

And on the log graph, we have the point (x, y) = ( 5,1)

Similarly  the point (-2, 1/25)  is on the exponential graph.....so the point ( 1/25, - 2) will be on the log graph

Here's an example using 10^x and log₁₀ x.............https://www.desmos.com/calculator/jbypfpwre3

Hope that helps.....

idk

Calculating the price of bond is a ralatively involved process. First, you have to figure out the the price of a stream of coupons. Second you have to find out the price of the par value of the bond at maturity, which is generally taken as $100. Then you add the two together to get the price of the bond.

But, what makes it even more complicated is the fact that the bond has to be priced on a specific date, i.e., the date of purchase, which is sometimes called "settlement date", which in this case is Monday, Nov. 2, 2015. So a special calculation has to be made for this odd period, from the last coupon date, June 1, 2015 to Nov. 2, 2015.

For this purpose, two different formulae are used to obtain the price of the bond: For the price of the coupons, this formula is used: PV=C[((1 + i)^n - 1)/((1 + i)^n.i)]. C=$4.00 par value of the coupon.

For the price of the par value of the bond at maturity, which is generally taken to be $100.00, this common formula is used: PV=100(1 + i)^-n. Where i=3/2=1.5, and n=number of semi-annual periods left in the life of the bond from Nov. 2, 2015 to June 1, 2030.

Putting all this together, it will be seen that the price of the bond on the purchase date of Nov. 2, 2015 will come to =$111.737 per $100. And the accrued interest=$1.683 per $100. This is for the period of June 1, 2015 to Nov. 2, 2015.

So, the total price of the bond is=$111.737 + $1.683=$113.420 per $100.00.

x / [ x + 1 ]  + 1/12  =  [x + 2] / [ x + 1 + 2 ]    simplify

x / [ x + 1 ] + 1/12  = [x + 2] /[ x + 3]    simplify the left side

[ 12x + x + 1 ] /  [ 12 (x + 1)]  = [ x + 2] / [ x + 3]

[ 13x + 1 ] / [ 12x + 12] = [ x + 2] / [x + 3]         cross-multiply

[ 13x + 1] [ x + 3 ] = [ 12x + 12 ] [ x + 2 ]    simplify

13x^2 + 40x + 3   = 12x^2 + 36x + 24   

x^2 + 4x - 21  = 0      factor

(x + 7) (x - 3) = 0          x = - 7  or   x = 3

Check -7

-7 / [ -7 + 1 ]  + 1/12  =  [-7 + 2] / [ -7 + 1 + 2 ]   

-7 / [ -6] + 1/12  = [-5] / [-4]   ???

14/12 + 1/12  = 5/4

15/12 = 5/4     and that checks

Check 3

3 / [ 3 + 1 ]  + 1/12  =  [3 + 2] / [ 3 + 1 + 2 ]   =

3 / 4  + 1/12 =  5 / 6

9/12 + 1/12  = 5/6

10/12 = 5/6      yep....that works, too

So ..we get two answers......the fractions are   7/6   and 3/4 

Here's the picture of your circle......the area of 31.24 cm^2 ≈  10pi cm^2.......the radius = 7.5

Tan=Opposite side/Adjacent side

Triangle MON ≈  Triangle QOP by AA congruency....therefore.....

OM / ON  = OQ / OP    Let  ON = x.....then OP  = 24 - x.......and we have

9 / x = 6 / [ 24 - x]    cross-multiply

9 [ 24 - x ] = 6x  simplify

216 - 9x = 6x      add 9x to both sides

216  = 15 x

x = 216/15  = 14.4 =  ON

And OP  = 24 - 14.4 =  9.6