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Alcohol equation is:  (6 x 0.64) + (X x 0.04) = Y x 0.44

Total fluid equation is:  6 + X = Y

Solve for X and Y

Answer is Y fl oz

90.

Tia  the answer is 9-luv kia

it all FUN!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

sqrt(3 +4i)=2+i

yes cuz potasium helps calm your nerves....i know this from experience

6 Pack

x < -14/11 

In (x, y)  form we would have

5(8/5) + 50   =  58

So, we would have

(8/5, 58)

@ 5% for 10 years: PV=$3,069.57

@ 7% for 7 years:   PV=$3,113.75

@9% for 4 years:    PV=$3,542.13

5(13x+18)<-4(14x+16)    simplify both sides

65x + 90 < -56x - 64       add 56x to both sides, subtract 90 from both sides

121x  < -154      divide both sides by 121

x < -154 / 121    [reduce the fraction ]

x < -14 / 11

6? i think

GEORGE BUSH

\(3w+2=w-4 \)

w = -3

how would i write this in (x,y) form

17x-13<3x        add 13 to both sides, subtract 3x from both sides

14x < 13          divide both sides by 14

x < 13 / 14

5h + 50  = 30h + 10    where h is the hours to equalize the costs....

Subtract 5h, 10 from both sides

40 = 25h    

Divide both sides by 25

40/25 = h  = 8/5 hrs

First of all, you ask how many hours "her" runs, first you told us it was a man, so we cant know how many hours she ran, it all depends on who you are asking about...

Or this is just a joke, the anwser is in the question...

2 is the answer

2.2

19.8 i think

Here's a pic of the situation......

A = Tortuga

B = Captain Jack's initial position

C = fishing vessel

The distance from the wreck to Tortuga = about 52.91 miles

BTW....this could be solved with the Law of Cosines, thusly....

AC = sqrt [ 20^2 + 40^2  - 2(20)(40)cos(120) ]

I just thought that the pic kinda' brought it all home a little better....!!!

I'm assuming you mean the power of the engine is 25 W. "effect" is a very broad term.

Power is rate at which work can be done, shown by its formula below:

\(P=\frac{w}{t}\)

P is power, w is work, and t is time. We'd use the equation for the power and work in your question.

\(25=\frac{100}{t}\)

\(t=\frac{100}{25}\)

\(t=4s\)

The engine would take 4 seconds.