All Answers 358172 Answers

0

x = log_3.3 (17)
= log_10 (17) / log_10 (3.3)
= 2.37302958849683

GuestMar 30, 2012

Mar 29, 2012

+3146

0

59/100=sin(3x-Pi/2)
asin( .. ) on both sides

asin( 59/100 ) =asin( sin(3x-Pi/2) )
asin( 59/100 ) =3x-Pi/2
+Pi/2 on both sides
asin( 59/100 )+Pi/2 =3x-Pi/2+Pi/2
asin( 59/100 )+Pi/2 =3x
divide both sides by 3
(asin( 59/100 )+Pi/2)/3 =3x/3
(asin( 59/100 )+Pi/2)/3 = x
x = (asin( 59/100 )+Pi/2)/3

[inputrad](asin( 59/100 )+Pi/2)/3[/inputrad]

[inputrad]59/100=sin(3x-pi/2)[/inputrad]

adminMar 29, 2012

+3146

0

[input](1/2) * (3/4)[/input]

adminMar 29, 2012

+3146

0

[input]plot( 2^x+5, x=-5..5)[/input]

adminMar 29, 2012

+8

0

Log3.3 (17) = x = 8.81473697792413

Assuming that the logarithm is base 10.

jeanlouisMar 29, 2012

+3146

0

36i is a imaginary number. (complex numbers)

def: i^2=-1

examples:

[input]sqrt( -49 )[/input]

[input](7i)^2[/input]

adminMar 29, 2012

+3146

0

[input]4*x=60[/input]

adminMar 29, 2012

+3146

0

[input]3x^2-5x-13=0[/input]

adminMar 29, 2012

0

a/b = x/y

You want to get x, so get everything to one side and leave x on the other side.

a*y/b = x

Now simply replace letters with numbers.

3*100/4 = x
x = 75

GuestMar 29, 2012

0

Get out of here with your pony c**p.

GuestMar 29, 2012

Mar 28, 2012

0

2 x 2 x 2 x 2 x 2 x 2
4 x 4 x 4
16 x 4
64

GuestMar 28, 2012

0

jrwolfe313:
what is 4 square root 3 times 11

Quote:
44 square root 3

GuestMar 28, 2012

0

if there's no square root for 340 then how do i solve it using radicals?

GuestMar 28, 2012

+3146

0

[input]8+sqrt(49)[/input]
[input]8-sqrt(49)[/input]

adminMar 28, 2012

+3146

0

[input]1/3 = 4/x[/input]

adminMar 28, 2012

+3146

0

[input]5254/525[/input]

adminMar 28, 2012

+3146

0

[input]-1.33333333333333334[/input]

adminMar 28, 2012

+3146

0

4f+3f+3=17
with: 4f+3f=7f
7f+3=17
-3 on both sides:
7f+3-3=17-3
7f=14
divide both sides by 7
7f/7 = 14/7
f = 2

[input]4f+3f+3=17[/input]

adminMar 28, 2012

+3146

0

[input]270/360 = (13x + 2)pi[/input]

adminMar 28, 2012

+3146

0

admin:
Good luck!
Ernie

very nice work.

adminMar 28, 2012

0

I didn't realize that you wrote in English ... sorry!

First use logarithm (ln or log) on both sides of the equation.
log (2*27^x)= log (9^(x-1))

use rules for logarithm

1) log (a*b) = log (a) + log(b)
log (2) + log (27^x)= log (9^(x-1))

2) log (a^b) = b*log (a)
log(2) + x*log (27) = (x-1)*log (9)

get rid of brackets by multiplying
log(2) + x*log (27) = x*log (9) -1*log (9)
or
log(2) + x*log (27) = x*log (9) - log (9)

all expressions that contain x are put on one side of the equation (by using + or -). the other expressions are put on the other side.
log (2) + log (9) = x*log (9) - x*log (27)

extract x on the right side
log (2) + log (9) = x*(log (9) - log (27))

divide by (log (9) - log (27))
x=(log (2) + log (9))/(log (9) - log (27))

don't forget to use brackets when you type it into the calculator!

Good luck!
Ernie

GuestMar 28, 2012

0

2(27)^x = 9^(x-1)
Ich gehe davon aus, dass zwischen 2 und der Klammer ein Mal steht. Wenn das der Fall ist, so ist die Klammer unnötig, und ich lasse sie gleich weg.

Zuerst logarithmieren auf beiden Seiten, entweder mit ln oder log.
log (2*27^x)= log (9^(x-1))

Dann Anwenden der Rechenregeln für log

1) log (a*b) = log (a) + log(b)
log (2) + log (27^x)= log (9^(x-1))

2) log (a^b) = b*log (a)
log(2) + x*log (27) = (x-1)*log (9)

Nun die Klammer (auf der rechten Seite) durch Ausmultiplizieren auflösen:
log(2) + x*log (27) = x*log (9) -1*log (9)
also
log(2) + x*log (27) = x*log (9) - log (9)

alle Ausdrücke, die x enthalten durch + oder - auf eine Seite bringen, die anderen auf die andere Seite
log (2) + log (9) = x*log (9) - x*log (27)

auf der rechten Seite x herausheben
log (2) + log (9) = x*(log (9) - log (27))

durch (log (9) - log (27)) dividieren
x=(log (2) + log (9))/(log (9) - log (27))

beim Eingeben in den Taschenrechner, die Klammern um den Nenner bzw. um den Zähler nicht vergessen!

Good luck!
Ernie

GuestMar 28, 2012

+3146

0

[input]4.9t^2+9.8t-7=0[/input]

adminMar 28, 2012

+3146

0

[input]5x^2-2x-3=0[/input]

adminMar 28, 2012

+3146

0

2*(27^x) = 9^(x-1)
ln on both sides:
ln( 2*(27^x) ) = ln( 9^(x-1) )
x * ln( 27 ) + ln( 2 ) = (x-1) * ln( 9 )
x * ln( 27 ) + ln( 2 ) = x * ln( 9 ) - ln( 9 )
x * ln( 27 ) = x * ln( 9 ) - ln( 9 )-ln( 2 )
x * ln( 27 ) = x * ln( 9 ) - ln( 9 )-ln( 2 )
x * ln( 27 ) -x * ln( 9 ) = - ln( 9 )-ln( 2 )
x * ( ln( 27 ) - ln( 9 ) ) = - ln( 9 )-ln( 2 )
x = (- ln( 9 )-ln( 2 )) / ( ln( 27 ) - ln( 9 ) )
[input](- ln( 9 )-ln( 2 )) / ( ln( 27 ) - ln( 9 ) )[/input]

adminMar 28, 2012

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