All Answers 358172 Answers

+3146

0

2*(27^x) = 9^(x-1)
ln on both sides:
ln( 2*(27^x) ) = ln( 9^(x-1) )
x * ln( 27 ) + ln( 2 ) = (x-1) * ln( 9 )
x * ln( 27 ) + ln( 2 ) = x * ln( 9 ) - ln( 9 )
x * ln( 27 ) = x * ln( 9 ) - ln( 9 )-ln( 2 )
x * ln( 27 ) = x * ln( 9 ) - ln( 9 )-ln( 2 )
x * ln( 27 ) -x * ln( 9 ) = - ln( 9 )-ln( 2 )
x * ( ln( 27 ) - ln( 9 ) ) = - ln( 9 )-ln( 2 )
x = (- ln( 9 )-ln( 2 )) / ( ln( 27 ) - ln( 9 ) )
[input](- ln( 9 )-ln( 2 )) / ( ln( 27 ) - ln( 9 ) )[/input]

adminMar 28, 2012

0

GuestMar 28, 2012

Mar 27, 2012

+3146

0

find the area of the complete circle (360deg), then calculate only the part of the full circle (135deg).

Area of full circle divided by (360/135) is the area of the "shaded" area.

adminMar 27, 2012

+3146

0

[input]x*0.6=100000[/input]

adminMar 27, 2012

+3146

0

x * 60/100 = 100000
x * 0.60 = 100000
x = 100000/0.60
[input]100000/0.60[/input]

adminMar 27, 2012

+6

0

R= P /I^2 or R= U^2/P or R= U /I

R= Resistance in Ohms
P= Wattage
I= Amperage
U= Volts

smjonesMar 27, 2012

+3146

0

0=5500(0.7)^t -3100
3100=5500(0.7)^t
3100/5500=(0.7)^t
t=log(3100/5500, 0.7)

[input]log(3100/5500, 0.7)[/input]

validation:
[input]5500(0.7)^(1.6074747903957) -3100[/input]

adminMar 27, 2012

+3146

0

[input]solve( x/3 + x/8 = 70, x)[/input]

adminMar 27, 2012

+3146

0

x=
[input]atan( 1.11 )[/input]

adminMar 27, 2012

+3146

0

[input]5/2=1/(3(x-2))[/input]

adminMar 27, 2012

+3146

0

[input]log(0.00008, 10)[/input]

[input]0.8 * 10^-4[/input]

adminMar 27, 2012

+3146

0

[input]5^-40[/input]

adminMar 27, 2012

+3146

0

[input]200$ * (1/0.06-1/0.06*(1+0.06)^10)*(1+0.06)^10[/input]

adminMar 27, 2012

+3146

0

[input]12 * (1+(66 2/3)/100 )[/input]

[input]100+20%-20%[/input]
100*(1+0.2)*(1-0.2)

[input](1+0.2)*(1-0.2)[/input]
factor is smaller 1, so it must be less that 100

adminMar 27, 2012

+3146

0

[input]8^3[/input]

adminMar 27, 2012

+3146

0

omega = sqrt( 1/(L*C) )

[input]sqrt( 1/( 13.8e-12 * 180e-9 ) ) / (2*pi)[/input]

[input]round( 100982085.57222155229107890415098 )[/input]

adminMar 27, 2012

+3146

0

[input]13(1/2)*13(3/2)[/input]

adminMar 27, 2012

0

I'm pretty sure it's 512 (:

GuestMar 27, 2012

+42

0

P=U.I I=U/R hence P= U^2/R and R=U^2/P

So R = 119.3^2 /144 = 98,8 Ohm

ricom39Mar 27, 2012

Mar 26, 2012

+3146

0

[input]int( x^3 , x)[/input]

adminMar 26, 2012

+3146

0

pyramid height:

0.12^2=sqrt(2*0.045^2)^2+h^2
0.12^2-sqrt(2*0.045^2)^2=h^2
h=sqrt(0.12^2-sqrt(2*0.045^2)^2)

volume of pyramid,
A= 1/3 * Area _base * h

[input]1/3 * (4.5cm*4.5cm) * sqrt( (12cm)^2-sqrt(2*(4.5cm)^2)^2) in cm^3[/input]

adminMar 26, 2012

0

admin:
8-5x = 2
+5x on both sides

8-5x+5x = 2+5x
8 = 2+5x
-2 on both sides
8-2 = 2+5x-2
8-2 = 2-2+5x
6 = 5x
divide both sides by 5
6/5 = 5x/5
6/5 = 1x
6/5 = x
x=6/5=1 1/5 = 1.2

[input]8-5x = 2[/input]

THIS IS RIGHT. but it's written TOO complicated.
here's an easier way:

8-5x = 2
+5x on both sides
-> 8 = 2 + 5x
-2 on both sides
-> 6 = 5x
then, to find out what the x is, you have to get to leave the x alone, so you divide it by 5 on both sides.
-> x = 6/5 ( six divided by 5 )
-> x = 1.2

HOPE THAT I HELPED YOU.

SINCERELY ALICIA.

GuestMar 26, 2012

0

i don't really understand your question brother from another motha.

GuestMar 26, 2012

+3146

0

[input]4/6-2/12=[/input]

adminMar 26, 2012

+3146

0

[input]975660000[/input]

adminMar 26, 2012

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