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i take math models and i dont really understand your question

i dont really know but can u tell me which lesson u are taking now so i can do it fast cause like with out boasting i am very great at math as well my dad

well actually what are u taking now so u can put it together

is coif coificent????

your welcome :))

okay, thank you! :)

do you see the 3 lines in the top right corner of the screen click that 

then click where you see history or Ctrl+H 

then another page will come up with your history 

at the top left of your page it should say "Clear browsing data" 

ok, umm, do you know the seaarch bar on top? like the web adress? im trying to clear the things i searched up in there. if that makes any since XD. so like, when i look up the website, i want it to show up like ive never been on it before. does that make any since? haha XD

Open Google Chrome.

2. Click the triple lines settings icon in the upper-right corner of the toolbar.

3. From the Tools option select Clear browsing data.

The clear browsing data tab will open via chrome://settings/clearBrowserData. Use the checkboxes to select the data you wish to clear out. Your options will depend on your current version of Chrome. Typical choices include the following: Clear browsing history, Clear download history, Empty the cache, Delete cookies and Clear saved passwords.

By using the Clear data from this period dropdown, you can select the period for which you want the data cleared. Time-based choices here include Last day, Last week, Last 4 weeks, or Everything.

5. Click the Clear Browsing Data button.

your welcome:))

try going to your laptop settings and look for internet or chrome :)

You are very welcome Hayley :)

Good night :)

ohhh. ok my bad! thank you so much for helping me, and having patience with me! i truly appreciate it :)

Wed 2/12/15

Etiquette for social posting

http://web2.0calc.com/questions/etiquitte-for-social-posting

Nauseated is back and the took us on a trip down memory lane.   Thanks Nauseated.

There are some really funny posts in this lot :

https://web2.0calc.com/questions/may-i-please-ask-a-question-about-history-i-m-really-struggling-everyone-is-so-helpful-on-here

https://web2.0calc.com/questions/the-jgughujgghjhgjgjhgjghjhgjggjhgj#r5

Sum of a series  1+1/2+1/3+1/4+........       Thanks Alan

https://web2.0calc.com/questions/infinite-sum

How wide is the river?  .   I always like ones like this   Thanks CPhill

http://web2.0calc.com/questions/two-ferry-boats-start-moving-at-the-same-instant-from-opposite-sides-of-a-river_1

Find the diagonal.   Good one for the juniors   Thanks Melody and CPhill

http://web2.0calc.com/questions/geometry_50964

I like your icon, that is a pretty photo :)

That is good Hayley but this in not about answering questions.

It is about absorbing any information that I give you about what is happening in the forum,

It is like a little newsletter :)

Just like any newsletter, some of it will be very important for you and some of it you will not need to worry about. :)

Thank you, you too! :)

Hi Hayley,

It is my turn to retire for the night.   It is 12:30 am here :)

 Enjoy your day :)

Well, I will answer as many questions as I can! and I will try to answer all the questions correctly! You have my word! :)

tan(pi/4) = 1

sec(pi/4) = sqrt(2)

tan(0) = 0

sec(0) = 1

You can finish it from here (use the calculator on the home page).

Hi Hayley,

I write one of these most days.

It is mainly designed to tell you that I have written a 'wrap'

In the sticky topics in the bottom right of the forum is a thread called 

"What is happening?  Wrap #4"

That is where my latest wraps are, but the address for it is the first blue address in the 'lantern'.

It is a hyperlink so you can jump straight over to my wrap from there :)

I'd really like you to look at it because sometimes it has things I would really like you to see.

It is how I communicate with the forum as a group.

There is information in there today that I think it is important for you to look at.    :)

"Here how did you get 3^2  ? it must be ( 5^2 - 3^2 ) according to ( Sf^2 - Si^2 ) ! ​ "

Sf and Si are the distances from the unstretched position.  So Sf = 2-5 (i.e. 3)  and Si = 5-5 (i.e. 0)

Oh! what is this about? :o