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2a+6

Julia sets?

Z² + C

Where " C " is an initial seed value.

Okay. If you made a 67 on a test that was worth 100 points, and you had no other grades in that class, then your grade in that class is 67 points out of 100. ( = 67% )

If you did 10 things in that class, and each was worth 50 points, you did perfectly on 6, made a 70% on 1, and made a 0% on 3, then you will have a (100% * 50 * 6  +  70% * 50  +  0% *50 *3) / (50*10)= 335/500. (=67%)

In both cases, your grade is a 67%.

But when you get a 30/30 on those packets, in the first case, your grade will increase to 97/130 = 74.6%

In the second case, your grade would increase to 365/530 = 68.9%

The more work you have done in that class so far, the smaller the impact those packets have on your grade.

I hope this helps.

He shot the guy to make sure he was dead. I think I've heard that before.

lmfao wow this just mad my day much more better....... :)

I guess i'm just a little bit confused, my grade in that class is a 67% i don't know what you mean with points. XD

I fixed it. You should get a 74.6% if you had a 67 out of 100 to start with and get a perfect score.

If you can, tell us out of how many points you have a 67%??

We can tell you a more accurate answer.

the third root ik but why did you put 1/3 not right......

Ok. Um. The total points for all 3 packets is 30(so it would be 30/30). in spanish 2, i have a grade of 67% so far, and i wanted to know what my grade would be if i got those 3 packets turned in correctly. :) sorry for the confusion!

what is the cube root of 125?

Cube root means " The third root", or:

125^1/3=5. This is the correct answer.

Is this a trick question or is that "someone" you? The 67% is worth what? 67/100? 335/500? What score was obtained on the 3 30 point packets?

Assuming you had a 67/100 in the class, and you made a perfect score on 3 30 point packets, you have a 74.6%. (67+30 / 100 +30 = 97/130) = 74.6%

If your original 67% was worth more points, (for example, if it was calculated from 335/500) then your grade would be closer to 67%.

yup because if all 3 packets were a 100% it will be the 300 then add that by 67 which is her grade before she did the packets so that will give you 367 then divide that by 4 which will give you 91.75 then round that which is 91.8%........ :))

Nu uh! are you sure?

125^3= 1953125

91.8%

Solve for x:
50 x^2+23 x-25 = 0

Divide both sides by 50:
x^2+(23 x)/50-1/2 = 0

Add 1/2 to both sides:
x^2+(23 x)/50 = 1/2

Add 529/10000 to both sides:
x^2+(23 x)/50+529/10000 = 5529/10000

Write the left hand side as a square:
(x+23/100)^2 = 5529/10000

Take the square root of both sides:
x+23/100 = sqrt(5529)/100 or x+23/100 = -sqrt(5529)/100

Subtract 23/100 from both sides:
x = sqrt(5529)/100-23/100 or x+23/100 = -sqrt(5529)/100

Subtract 23/100 from both sides:
Answer: | 
| x = sqrt(5529)/100-23/100                    or x = -23/100-sqrt(5529)/100

Hallo guest!

3/5(x+2) = x-4       |*5

   3(x+2) = 5x-20

     3x+6 = 5x-20   |-5x

    -2x+6 = -20      |-6

        -2x = -26      |:(-2)

           x = 13

sorry

Hmm. 2 different answers. :o

Ibealive that you can put this into your caluclator yourself . :) Did you just type up random numbers?

Hallo guest!

3/5(x+2) = x-4       |*5

   3(x+2) = 5x-20

     3x+6 = 5x-20   |-5x

    -2x+6 = -20      |-6

        -2x = -14      |:(-2)

           x = 7

Add up all the three expenses and subtract their total from 30 pounds. That is how much she has left.

Solve for x:
(3 (x+2))/5 = x-4

Multiply both sides by 5:
(5×3 (x+2))/5 = 5 (x-4)

(5×3 (x+2))/5 = 5/5×3 (x+2) = 3 (x+2):
Answer: | 3 (x+2) = 5 (x-4)
|             x=13