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-3   [   1   -2     0      -4      4  ]

               -3   15     -45  147

        ------------------------------

           1  -5   15    -49   151

Check the graph here...   https://www.desmos.com/calculator/ixujxbczbk......at P(-3)   the value of the polynomial = 151

great ! :)

well im going to be a member than

Thanks for saying thx! No a lot of guest use there manners :)

thx

Mr. Chris is here. :) hes  a lot better than I am. :)

15 * 18

= 270Ft^2

:)

Yeah maybe

Use synthetic division to find P(-3) for P(x)= x^4 -2x^3 - 4x + 4.

(-3)^2 - 2(-3)^3 - 4(-3) - 4

   9          -54      12    -    4

-61.

I don't know if im correct or not . . .

If x,y, and z are positive integers and 3x = 4y = 7z, what is the least possible value of x+y+z?

Note........if 3x = 4y,    then    y = [3/4 ] x

And if 3x = 7z, then   z = [ 3/7]x

So

x +  y + z =

x + [3/4]x + [3/7]x  =

If y and z are integers, then  28 [ the common denominator of 3/4 and 3/7]  is the smallest  possible integer for x

And y = [3/4]x =  [3/4] * 28 =  21

And z = [3/7]* 28 = 12

So.....the minimum  value for   x +  y + z =  28 + 21 + 12 =     61

[Edited for an earlier mistake......I forgot that all three had to be integers....]

I think you would plug "-3" into all those X's . .. Am I corrext? Or no :/

If x,y, and z are positive integers and 3x = 4y = 7z, what is the least possible value of x+Y+Z?

Since the LCM of: 3, 4, 7 is=84, therefore

x=84/3=28

y=84/4=21

z=84/7=12

Guest beat me (: . I typed to slow. lol

Set the factor '(-4 + -1x2)' equal to zero and attempt to solve

: Simplifying

-4 + -1x2 = 0

Solving

-4 + -1x2 = 0

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation

. -4 + 4 + -1x2 = 0 + 4

Combine like terms: -4 + 4 = 0

0 + -1x2 = 0 + 4 -1x2 = 0 + 4

Combine like terms:

0 + 4 = 4 -1x2 = 4

Divide each side by '-1'.

x2 = -4

Simplifying

x2 = -4

:}

Thanks!

Solve for x:
x^4-41 x^2 = -400

Add 400 to both sides:
x^4-41 x^2+400 = 0

Substitute y = x^2:
y^2-41 y+400 = 0

The left hand side factors into a product with two terms:
(y-25) (y-16) = 0

Split into two equations:
y-25 = 0 or y-16 = 0

Add 25 to both sides:
y = 25 or y-16 = 0

Substitute back for y = x^2:
x^2 = 25 or y-16 = 0

Take the square root of both sides:
x = 5 or x = -5 or y-16 = 0

Add 16 to both sides:
x = 5 or x = -5 or y = 16

Substitute back for y = x^2:
x = 5 or x = -5 or x^2 = 16

Take the square root of both sides:
Answer: | x = 5   or x = -5   or x = 4   or x = -4

I'll try to help in anyway I can. One moment please!!

Yeah haha

oh . . . these again .

Notice that since 3, 4, and 7 are co-prime (they don't share any common factor but 1), then: {nl} {nl} x must be a multiple of 4 and 7, so the least value of x is 28 (LCM of 4 and 7); {nl} y must be a multiple of 3 and 7, so the least value of y is 21; {nl} z must be a multiple of 3 and 4, so the least value of z is 12; {nl} {nl} So, the least possible value of x + y + z is 28+21+12=61.

Then add then them up, then divide by 61.

So you're answer is..

1 :)

Or simply just 61. :)

What quartic functions?????...........

Here's one possibility.... (x + 1)^2 * (x + 3)^2

I was going to answer, but ally & Mr. Chris beat me to it :)