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i know i just copied it from the calcutltor.

Don't ADD them, but separate them by commas " , " and we can tell you very quickly.

secx tanx - secx = 0   factor out the secx

secx [ tanx - 1]   = 0 

So     either the sec x = 0    which is impossible .....  or ......

tanx - 1  = 0  →    tanx = 1      and this occurs at   pi/4 + n*pi   where n is an integer 

secx tanx + secx = 0     again, factor out the secx

secx [ tax + 1]  = 0

secx = 0  is impossible

tanx + 1  = 0

tan x = -1       and this occurs at  3pi/4  + n*pi     where n is an integer

The graph here shows only one real root.......https://www.desmos.com/calculator/8xro919zxo

It occurs at about ( 13.91, 0 )

Excellent, Hayley.....!!!

What are all the real zeros of y=(x-12)^3 - 7?

x = 12-(-7)^(1/3),   x = 12+7^(1/3),   x = 12+(-1)^(2/3) 7^(1/3)

Sorry, Hayley........but this one is a Calculus problem......it's a good one, but a little tricky.....

L + W + H  = 6

L = 1.5 H

Let x  = H        then    L  = 1.5 x        and W =  6 - L - H   =  6 -  1.5x - x   =  6 - 2.5x

So.......the volume - V -  is given by

V = H * L * W

V = x *( 1.5)x * [ 6 - 2.5x ]  =

V = 1.5x^2 *[ 6 - 2.5x]  =

V =  9x^2 - 3.75x^3        take the derivative and set to 0

V '  =  18x - 11.25x^2 =  0     factor

x [ 18  - 11.25x]  = 0 

So either x = 0   [reject]

Or

18  -  11.25x  = 0

11.25x  = 18       divide both sides by 11.25

x = 18  /  11.25   = 1.6  units........this is the height

1.5x  = 1.5(1.5)=  L =   2.4 units

And the  width, W,  =  6 - 2.5x =  6 - 2.5(1.6)  =   2 units

Here's the graph of the function in terms of  x ........https://www.desmos.com/calculator/fhmdwdkprw

Note that a max volume of 7.7 cubic units occurs when x = 1.6

(a + b)^6 will have 7 terms so you want row 6 of the triangle 1 6 15 20 15 6 1 
so (a + b)^6 = a^6 + 6a^(5)b + 15a^(4)b^2 + 20a^(3)b^3 + 15a^(2)b^4 + 6ab^5 + b^6 
given a = d and b = -5y 
∴ (d − 5y)^6 = d^6 + 6d^(5)(-5y) + 15d^(4)(-5y)^2 + 20d^(3)(-5y)^3 + 15d^(2)(-5y)^4 + 6d(-5y)^5 + (-5y)^6 
∴ (d − 5y)^6 = d^6 − 30d^(5)y + 3755d^(4)y^2 − 2500d^(3)y^3 + 9375d^(2)y^4 − 18750dy^5 + 15625y^6

ohh?

Here is CPhill's answer:

It I entered everything correctly...........

The sum of the numbers = 2699

There are 36 values

So.....the mean =   2699 / 36  = about 74.972     [the final 2 repeats]

WHICH IS THE SAME AS GUEST #3 ANSWER.

LOL

No you not be reported but you are a cat and we might let the dogs out.

Who let the dogs out boom ba ba boom ba  boom . . . who let the dogs out boom ba ba boom 

Who . . .  who . . .  who  . . .

hahaha

evaluate arcsin (-1/2)=-30

See my answer, here.........https://web2.0calc.com/questions/mean_93229

Find the median of the list:
(57, 61, 62, 64, 65, 66, 68, 69, 70, 70, 71, 72, 73, 73, 73, 74, 75, 76, 77, 77, 78, 78, 79, 79, 80, 80, 80, 81, 82, 82, 83, 83, 83, 84, 86, 88)

The two elements in the middle of the list (57, 61, 62, 64, 65, 66, 68, 69, 70, 70, 71, 72, 73, 73, 73, 74, 75, 76, 77, 77, 78, 78, 79, 79, 80, 80, 80, 81, 82, 82, 83, 83, 83, 84, 86, 88) are 76 and 77:
(57, 61, 62, 64, 65, 66, 68, 69, 70, 70, 71, 72, 73, 73, 73, 74, 75, 76, 77, 77, 78, 78, 79, 79, 80, 80, 80, 81, 82, 82, 83, 83, 83, 84, 86, 88)

The median is the average of the two middle elements, 76 and 77. This average is:
Answer: | (76+77)/2  =  153/2=76.50

It I entered everything correctly...........

The sum of the numbers = 2699

There are 36 values

So.....the mean =   2699 / 36  = about 74.972     [the final 2 repeats]

check ur anwser agian tooo

76.5

Solve for x:
x^4-6 x^2-7 x-6 = 0

The left hand side factors into a product with three terms:
(x-3) (x+2) (x^2+x+1) = 0

Split into three equations:
x-3 = 0 or x+2 = 0 or x^2+x+1 = 0

Add 3 to both sides:
x = 3 or x+2 = 0 or x^2+x+1 = 0

Subtract 2 from both sides:
x = 3 or x = -2 or x^2+x+1 = 0

Subtract 1 from both sides:
x = 3 or x = -2 or x^2+x = -1

Add 1/4 to both sides:
x = 3 or x = -2 or x^2+x+1/4 = -3/4

Write the left hand side as a square:
x = 3 or x = -2 or (x+1/2)^2 = -3/4

Take the square root of both sides:
x = 3 or x = -2 or x+1/2 = (i sqrt(3))/2 or x+1/2 = 1/2 (-i) sqrt(3)

Subtract 1/2 from both sides:
x = 3 or x = -2 or x = (i sqrt(3))/2-1/2 or x+1/2 = 1/2 (-i) sqrt(3)

Subtract 1/2 from both sides:
Answer: | x = 3   or x = -2   or x = (i sqrt(3))/2-1/2   or x = 1/2 (-i) sqrt(3)-1/2

I forgot to put the numbers here they are 57, 61, 62, 64, 65, 66, 68, 69, 70, 70, 71, 72, 73, 73, 73, 74, 75, 76, 77, 77, 78, 78, 79, 79, 80, 80, 80, 81, 82, 82, 83, 83, 83, 84, 86, 88

I get a slightly different answer: 2699/36=74.972

Check it once again.