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This is the question that you have asked.  Is it the question that you intended ?

If not then you will need to add appropriate brackets :)

(5^2/3xy^-2z^1/2)^3/2

\(\frac{(\frac{5^2}{3}xy^{-2}z^{1/2})^3}{2}\)

18+2*1+3^2=38

18 + 2*(1 + 3^2)  =

18 + 2* (1 + 9)  =

18 + 2*(10)  =

18 + 20  =

38

The problem Chris is 

\(\boxed{\frac{-\pi}{2}<tan^{-1}x<\frac{\pi}{2}}\)

You are saying that  tan^-1x = 5pi/6  or  7pi/6

Both these values are outside the range of the function tan^-1x

6*7-3*4+1=27

( 6*7 ) - 3*(4 + 1)  =

42 - 3(5)  =

42 - 15  =

27

Consider, Melody........

Since the secant is negative,  this angle has to be either in the second or third quadrant

If x = -1/sqrt(3)   then    arctan( -1/sqrt(3))  =   -pi/6  = -30°

But this would actually be a 30° angle in the second quadrant since both the secant and arctan are negative.......thus ....arctan (-1/sqrt(3))  = 5pi/6

If x = 1/sqrt(3), then the arctan (1/sqrt(3)) = pi/6  = 30°

But.......this would have to be a 30° angle in the third quadrant because the arctangent of an angle in that quadrant would be positive while, again, the secant is negative, so,  arctan(1/sqrt(3)) = 7pi/6

Check for yourself that  sec (5pi/6)  = sec(7pi/6)  = -2/sqrt(3)

Alan or Bertie can you please talk me through this.  I can't bet my head around it :(

sec(Tan^-1(x))= -2/sqrt3

let tan^-1x=theta

then

tan (theta)=x

\(sec(\theta) = \sqrt{1+x^2}\)

now it doesn't matter if x is positive or negative sec(theta) has to be positive. SO

I don't think that there should be any solutions. 

Here is a graph to back up what I am saying

https://www.desmos.com/calculator/dutfolqi6o

This page also seems to back up what I am saying

7000(1 +.04/2)^{8 * 2}  =  7000(1.02)¹⁶  =  about $9609.50

8 * (1/2)   = 8/2    =  4

(1) Large Male Cod: 12

(2) Small Female Herring: 11

(3) Large Cod: 31

(4) Male Cod: 29

(5) Large Males (Fish): 35

(6) Cod total: 69

(7) Male (Fish) total: 68

(8) Large fish total: 72

Total fish caught: __

(3) Large Cod - (1) Large Male Cod  = 31 - 12  = 19 = Large Female Cod

(8) Large Fish Total -  (5) Large Males  = 72 - 35  = 37  = Large Females

Large Females - Large Female Cod = 37 - 19  = Large Female Herring = 18

Total Female Herring = Small Female Herring + Large Female Herring = 11 + 18 = 29

(7) Male Fish - (4) Male Cod  = 68 - 29 =  39  = Male Herring

So.......Total Male and Female Herring   = 39 + 29 = 68 = Total Herring

So.....(6) Total Cod + Total Herring  = 69 + 68  = Total Fish  137

My rules

1. Love dogs
2. By a house big for all my dogs
3. Have a husband that likes dogs
4. Have a cute husband
5. Own a lot of dogs
6. $$$$$$$$$$
7. Have a ton of $$$$$$$$$$$$$$$$$

5 1/2% of what number =82

Let x be the number, then we have:

.055x=82 divide both sides by .055

x=82/.055

x=1,490.91

Post answer/question into word first, then copy over.

I'm assuming this a joke question, but in case it's not...

How do you listen to music over the radio? Lot's of math involved + calculus.

How can you tell how fast your car is going? Calculus!

How do you think your videogames work? Lot's of complex algorithms and math.

How can you predict how much money a company would earn?

You know that thing you used to post that question? Like you know, that computer? How does it work?

There are so many practical applications of math... without math this world will be in flames and civil war.

[OP]

The better explained guide was pretty good to start... but imo the autho tied it up really badly at the end.

I found this: http://practicalcryptography.com/miscellaneous/machine-learning/intuitive-guide-discrete-fourier-transform/

This guide was actually alot better and understandable for me... It answered virtually all my questions.

Thanks for that.

Hi Guest,

It is a good idea but CPhill and I have nothing to to do with the programming of the site.

I think Admin is fully occupied with just keeping the present functions working properly.

Thanks Admin :)

sec( arctan(x)) = -2/sqrt(3)

Let arctan(x)  = theta      .....then we have

sec(theta) = -2/sqrt(3)   using the secant inverse

arcsec (-2/sqrt(3))  =  theta = 5pi/6

Then.......we are looking for the tangent of 5pi/6  = x =  -1/sqrt(3)

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As an edit.....the secant could also = -2/sqrt(3) at 7pi/6......in that case, the tangent of 7pi/6 = x  =  1/sqrt(3)

math is important to know how many apples you have and how many your friends indepted money to you

I don't know why it said 2:54 am cuz that's not when I did that but oh well

i think this way is easear

sqrt{X+\sqrt{X+\sqrt{X+...}}}=5

sqrt{5x4+\sqrt{5x4+\sqrt{5x4+...}}}=5 if it is + you will bring 5 if it is - you will bring 4

let s say:

sqrt{12+\sqrt{12+\sqrt{12+...}}}=x

we can write it like 

sqrt{4x3+\sqrt{4x3+\sqrt{4x3+...}}}=x  so x will be 4 because + we choosing bigger one 

math is important becuse without it we wouldn't know how much we have of something and other calamitys like that. it also helps with logic as well 

we have to know the original price b4 discount - owner 

We have to know either the original price of the computer before discount, or we have to know the tax rate as %.

Ya should find the money that paid in 6 equal months- owner 

5+3=8    8-7=1    1 is the answer

And btw if you did this for a joke please don't because it takes up forum room for real questions