CPhill: kayla121497 wrote:point A is the center of the sphere. point C is on the surface of the sphere. point B is the center of the circle that lies in plane P and includes point C. the radius of the circle is 12mm. AB= 5 mm. What is the volume of the sphere to the nearest cubic mm?
Mmmmm....I don't know about this.....here's a cross-section of a sphere where A is the center, C lies on the sphere's surface and AB =5, BC = 12 and BC lies in Plane "P"
(I think all of these meet the requirements of the problem).
Circle.JPG
Note that the radius of the sphere is ≈ 10 (At least as close to 10 as I could make it!!)
Maybe I'm reading too much into this problem, but I claim that we don't actually know that BC is at a right angle to AB
I guess my point is that we could have a right triangle, but as you see, it might not have to be. Note that ∠BAC is greater than a right angle
In hindsight, the problem only "works" if we assume that AB is perpendicular to BC.......and since we're not given any other information, then DavidQD and Alan would certainly be correct !!!