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I would do,

800 * 6

Which would make it, 4800

Hi jc! 

Since the beginning of 2002,the number of student in Spring Lake high school has doubled every 3-year period. If there were 800 students in the school at the beginning of 2002,how many students are in the school at the beginning of 2008?

112 1/2  x  19 2/5     IF you have (and are allowed to use) a fraction calculator, that is fine, o/w:

112 1/2  =   225/2    19 2/5 =  97/5

then    225/2   x  97/5  =  (225 x 9) / (2 x 5)  = 2025/10 =  202.5    or  202 1/2

That's a slap in the face for yea, Mob

LOL! Not all women are lazy!

I mean why would I know how to speak dead languages if I was lazy?

And why would I even respond to this post.....?

Please I want to F.U.C.K a women because they are as lazy as F.U.C.K

yah let's not not make cuss words :)

Lets not and say we did

Let's NOT.....

i think guest s answer is best

I've been anoying you sence the start does that count?

Subtract equation 2 from equation 1 to get:

5y = 20   or  y =4

Sustitute y = 4 into EITHER equation to find 'x'   5x + 3 (4) = 17   5x = 5    x = 1

Comes up '0' for me....    is your calculator in 'degrees mode'  (lower left)  

enter 270    then cot  then =     and I get '0'

5x+3y=17

+

-5x+2y=3

=

5y=20

y=4

x=1

Systems of equations 

5x+3y=17

5x-2y=-3 

5x+3y=17

minus

5x-2y=-3

5x+3y-(5x-2y)=17-(-3)

5x+3y-5x+2y=20

5y=20

y=4

Solve the following system:
{5 x-2 y = -3 |     (equation 1)
5 x+3 y = 17 |     (equation 2)
Subtract equation 1 from equation 2:
{5 x-2 y = -3 |     (equation 1)
0 x+5 y = 20 |     (equation 2)
Divide equation 2 by 5:
{5 x-2 y = -3 |     (equation 1)
0 x+y = 4 |     (equation 2)
Add 2 × (equation 2) to equation 1:
{5 x+0 y = 5 |     (equation 1)
0 x+y = 4 |     (equation 2)
Divide equation 1 by 5:
{x+0 y = 1 |     (equation 1)
0 x+y = 4 |     (equation 2)
Collect results:
Answer: | {x =1  and y=4}
 

It might help to SEE how to do this:

-1/8  /  9/4   is EQUAL to  -1/8  x  4/9    (Ya see?....I took the lower fraction and flipped it over and turned it into a MULTIPLICATION problem)

-1/8  x  4/9   =  -4/72   =  -2 /36 =  -1/18

Olivia .....you forgot the NEGATIVE sign !

3/8   is equal to  3  divided by 8

if you do that you will get the decimal   .375

For a percentage, you have to multiply this answer x 100     or   .375 x 100% = 37.5%

In 1990, the population of Austin, TX, was 494,290. During the next ten years, the population increased by 3% each year. What would you expect the population to be in 2007?

The population of Austen, TX will be=664,284 in the 10-year period from 1990-2000.

If the poulation contiues to increase at the same rate of 3% per year, then Austen, TX population in 2007 will be=816,986 people.

It is true.The communitive and associative property allow you to move and group different numbers together. Hope this helps!

This problem is a lot like some of the financial questions we see here on the forum....

There is an equation which will serve you well to remember....it is one of the most commonly used financial equations....there are a few more (actually there are BOOKS of them)

FV = PV (1 + i)^n     FV = Future value (or POPULATION in this example)  PV = PRESENT value (of the population)

                                  i = interest in decimal form ( rate of growth in this question .03)    n= number of periods (years)

So substitute    FV =  494,290 (1 + .03)^17      n = 17 (from 1990 to 2007)    

                             = 816986 people     This ASSUMES that the population increase is 3% for all of the years from 1990-2007

~jc

-1/8 divided by 9/4=1/18

Your snow is finally coming too us!