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Thanks Guest :))

 

x-y=3 then x^3-y^3-9xy =?

 

This is fascinating.  Look at this weird graph!

https://www.desmos.com/calculator/dbawqgablq

 

Now for the algebra.

x-y=3

so

y=x-3

 

Find what x^3-y^3-9xy =

 

\(x^3-y^3-9xy\\ =x^3-(x-3)^3-9*x(x-3)\\ =x^3-[x^3-3(x^2*3)+3(x*3^2)-3^3]-9x(x-3)\\ =x^3-[x^3-9x^2+27x-27]-9x^2+27x\\ =x^3-x^3+9x^2-27x+27-9x^2+27x\\ =9x^2-27x+27-9x^2+27x\\ =27 \)

 

Cool!

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