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Not really... Nobody wants to focus on school on the weekend.

Solve for X:
35+X (X-6)+X (X+3) = X (X-5)+X (X+7)

Expand out terms of the left hand side:
2 X^2-3 X+35 = X (X-5)+X (X+7)

Expand out terms of the right hand side:
2 X^2-3 X+35 = 2 X^2+2 X

Subtract 2 X^2+2 X from both sides:
35-5 X = 0

Factor constant terms from the left hand side:
-5 (X-7) = 0

Divide both sides by -5:
X-7 = 0

Add 7 to both sides:
Answer: | X = 7

x+1.2=-1.8

find the x

-3

what is -0.124 which is also a repeating decimal converted into a fraction ??

If ONLY 4 repeats .-124444444444........then the fraction is: -28/225

If ONLY 24 repeats.-.12424242424........then the fraction is:-41/330

If the whole number repeats, -.124124124124.....then the fraction is:-124/999.

(mg⁴)^-1(m¹g⁴)  =

(m^-1g^-4)(m¹g⁴)  =

(m⁰g⁰)  =

(mg)⁰  =

1

you are asking for the same thing again and again look at the other samples and do it by yourself 

it s a pythagorean theorem: \(a^2+b^2=c^2\)

sqrt(400^2 + 1050^2)  = about 1123.6 ft

sqrt(7^2  + 10.5^2)   = about 12.6 blocks

58 feet is the HYPOTENUSE  and the OPPOSITE leg is 23.6

Pythagorean theorem    58^2 = 23.6^2 + Base^2     Base = 52.98 ft

Brothers or apples?   Maybe he killed his brother for taking his apple!

We can use the pythagoron theorem a^2+b^2=c^2

16+x^2=14^2

sqrt(180) = 13.4164078649987382

13.42 feet high

Guest

For the airplane problem

 sin 55 = (30000ft/distance)     Solve for distance =36,623.23 ft

For the airplane problem

 sin 55 = (30000ft/distance)     Solve for distance =36,623.23 ft

Francesca is looking at an airplane. She measures the angle at which she is looking up and finds it to be 55 degrees. If the airplane is traveling at an altitude of 30,000 feet, about how far is the airplane from Francesca?

Pull one shoe out and there are 9 shoes left in the bag  ONE matches and EIGHT do not match....there are then EIGHT ways to pull out a shoe that does not match.

ARCTAN (1/4) = 14 degrees

My turn:

what I did to a Pats fan yesterday

Hey Spawning Angel.... there are 5 PAIRS of shoes in the bag...how does that change your calc???

Sorry, reposted

Since the height difference is 2, theams that 2 is one fo the side lengths

You can find this using the fact that the triangle's base is starts at roughly the top of Imelda's head.

The other side length is 9, since they are 9 feet apart.

We use the pythagorem theorem to find the hypotenuse a^2+b^2=c^2

4+81=sqrt(85)

Using sin(x)=2 over sqrt(85) we can find the angle of elevation

asin(2/sqrt(85)) = 0.218668945874

This is in radians

We can multiply by 180/pi to turn this into degrees

0.218668945874*((180)/pi) = 12.5288077091548361

We round to the nearest degree and our anwser is 13 degrees of elevation

If you draw the picture of this you will see that her eyes are 4 feet off of the ground at one vertex of a triangle and another vertex is at 4 feet off of the ground on her father and the other vertex is at her father's head....

Two legs of the triangle are 2 and 9 feet    of a RIGHT triangle    the TANGENT of the angle is   2/9  so the angle is

arctan(2/9) = 12.53 degrees

Using Law of cosines, you'll find the smallest angle is between the  34 and 47 sides and = 29.23 =29 to the nearest degree.

24^2 = 34^2 + 47^2 - 2(34)(47)COS(angle)  

See:  http://mathworld.wolfram.com/LawofCosines.html      for a good  description of Law of Cosines

Combination: A set of objects in which position (or order) is NOT

important.=nCr=10C2=45

You can pull any 5 on the first try, then any of the last 4 on the second try

5*4=20

Thats just the logically way to do it.

I don't know if your teacher has you doing it a defferent way