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We know:)

Great question! How do you know??

Well.. Wouldn't it depend on the question itself??

Simplifying

-11y + 13x = -12

Reorder the terms:

13x + -11y = -12

Solving

13x + -11y = -12

Solving for variable 'x'

. Move all terms containing x to the left, all other terms to the right.

Add '11y' to each side of the equation

. 13x + -11y + 11y = -12 + 11y

Combine like terms: -11y + 11y = 0

13x + 0 = -12 + 11y

13x = -12 + 11y

x = -0.9230769231 + 0.8461538462y 

Wouldn't the "x,y" be "0"s??

;))))))))).

Same here >.<

Oh my fav!! * Scarcasm *

45$

I sent thema  messege. The person logged off right after.. =.=

Ditto what Coldplay and Hayley said......

And why the " or nah"?? :p

Potential energy = (mass) x (gravity) x (height above the reference)
 Relative to the 70th floor, on which the refrigerator is standing,
                 PE = (75 kg) x (9.8 m/s²) x (0)  =  0 joules .
Relative to the 35th floor, halfway up to where the fridge is standing,
              PE = (75 kg) x (9.8 m/s²) x (150 m)  =  110,250 joules .
Relative to the ground,
                  PE = (75 kg) x (9.8 m/s²) x (300 m)  =  220,500 joules .

LOL Hayley! U should go talk to ur BFF, lol:)

That's great!

Probably because we don't really know each other well

Omg YAY!! I'm SOO Happy for you!! * Hugs *!!!

Factor the following: 48 x^2+48 x y^2+12 y^4 Factor 12 out of 48 x^2+48 x y^2+12 y^4: 12 (4 x^2+4 x y^2+y^4) 4 x^2+4 x y^2+y^4 = 4 x^2+4 x y^2+1 (y^2)^2: 12 4 x^2+4 x y^2+(y^2)^2 The factors of 4 that sum to 4 are 2 and 2. So, 4 x^2+4 x y^2+(y^2)^2 = (y^2+2 x) (y^2+2 x): 12 (y^2+2 x) (y^2+2 x) (y^2+2 x) (y^2+2 x) = (y^2+2 x)^2: Answer: | | 12 (y^2+2x)^2

Scarcasm. This person has been VERy rude. :/

12 • (2x + y2)^2

((48•(x2))+(48x•(y2)))+(22•3y4)

 Pull out like factors :

   48x2 + 48xy2 + 12y4  =   12 • (4x2 + 4xy2 + y4) 

    4x2 + 4xy2 + y4 

 :  (2x + y2)•(2x + y2)

 4x2  +4xy2  +y4  
 

12 • (2x + y2)2

:D :D

go look at my new post 

and hayley1 why did u put friend in " "?

Ok,

I just type in "3.14"

* nods *

Vic? Coldplay?

Hey, Vic! Our " Friend " is online . . ..