Call x the number of 2 pointers he made and y the number of 3 pointers he made.....and we have...
x + y = 9 → y = 9 -x (1)
2x + 3y = 21 (2)
Subbing (1) into (2) for y, we have
2x + 3[9 - x] = 21 simplify
2x + 27 - 3x = 21
-1x + 27 = 21 subtract 27 from both sides
-1x = -6 divide both sides by -1
x = 6 and y = 9 - 6 = 3
So.....he made 6 two pointers and 3 three pointers
Here's the Desmos Graph anyway......you can work around it....!!!
https://www.desmos.com/calculator/pq1gbjphgz
