Open an account...otherwise you ae just lumped in as 'guest' and no one knows who you are......
There was SEVENTEEN people signed in this morning.....
Got it... Thanks, Chris
Go ahead and ask your question, Kellogg......we'll see if we can help you.....
Thanks, heureka........what method did you use for your solution?????
Why would you ask that?
Dicturus enim sum ...
Oh, Sorry.. My bad.
Not criticizing.
Yes I suppose. Also you spelled site wrong. XD.
W*F brooo. lol
(not trying to be rude.)
I was looking to see how reliable other peoples' answers were, because I'm new to the site**... but It just doesn't look helpful.. you know?
Please don't spam!!!
There's no point if you ask that if you are not really asking a math related question.
Go online and try this statistics calculator and see if it will help you solve the problem:
http://www.hackmath.net/en/calculator/statistics
It's just that I was reading through the feed and most of this isn't really any actual help, it's just people messing around. I was signing up to get real help, because I thought this was like Slader.com because my school blocked it on the computers, but this isn't as helpful at all.
What r u using to translate!!! That's horrible translation!
We are using the ring ["washer"] method........see the explanation, here....
http://tutorial.math.lamar.edu/Classes/CalcI/VolumeWithRings.aspx
[Example 1 is very similar to this one]
You haven't asked a question. I don't really know too many answers for some of these questions. It also takes time for people to answer questions.
And you have just said:
"does not mean that you have not read ... I do not ..."
Hey CPhill..... it says 9-x^2 Where did you get (9-x^2)^2 Hmmmmm....
ipsa DS , im ... imprimi,
Area = pi * (radius)^2 = pi * (21 in)^2 = [ pi *441] in^2 ≈ 1385.44 in ^2
Coldplay just said:
"Fool! You are so dumb! It is easy to, and you know the answer!
The answer is 19, by the way.
I THINK it is Integral (0-2pi) Integral(0-2) 9-x^2 I think! 30 2/3 pi Yikes....that is a wild guess. Let me know when soemeone is able to ACTUALLY answer it .....
