$349.99 X 1.41 =$493.49 Cost of the puppy after markup but before discount.
$493.49 X .77 =$379.99 Cost of the puppy after 23% discount
Is this the PRICE of the puppy?
Cost would be 349.99/.77 1/1.41 322.36
IF this is the cost of the puppy which is then marked up 41% then discounted 23% the final price would be
(349.99 x 1.41) x .77 = 379.98
488.56
f(x)=2*(integral from x=0 to x=x of 1/(1+3f^2(t)) dt ))=
f(x) = (2 x)/(3 f^2 t+1)
Find integral from x=0 to x=1 of (f(t) dt)
Compute the definite integral: integral_0^1 f(t) dx Apply the fundamental theorem of calculus. The antiderivative of f(t) is x f(t): = x f(t)|_(x = 0)^1 Evaluate the antiderivative at the limits and subtract. x f(t)|_(x = 0)^1 = 1 f(t)-0 f(t) = f(t): Answer: | | = f(t)
CPhill is also correct.
First of all, put it in the Web2.0Calc.... XD
Then you get this:
sqrt3(5)-x=sqrt(5 = x=sqrt3(5)-sqrt(5)
The answer is approximately 0.5261
cuberoot (5) - ? = sqrt (5) add ? to both sides, subtract sqrt(5) from both sides
cubroot(5) - sqrt(5) = ?
Yep, Rarinstraw.....a photo finish.....!!!!!
GOOFBALL!!
Wow CPhill! Exact same time! :P
Compute the definite integral: integral_0^2 pi (9-x^2)^2 dx Factor out constants: = pi integral_0^2 (9-x^2)^2 dx Expanding the integrand (9-x^2)^2 gives x^4-18 x^2+81: = pi integral_0^2 (x^4-18 x^2+81) dx Integrate the sum term by term and factor out constants: = pi integral_0^2 x^4 dx+-18 pi integral_0^2 x^2 dx+81 pi integral_0^2 1 dx Apply the fundamental theorem of calculus. The antiderivative of x^4 is x^5/5: = (pi x^5)/5|_0^2+-18 pi integral_0^2 x^2 dx+81 pi integral_0^2 1 dx Evaluate the antiderivative at the limits and subtract. (pi x^5)/5|_0^2 = (pi 2^5)/5-(pi 0^5)/5 = (32 pi)/5: = (32 pi)/5+-18 pi integral_0^2 x^2 dx+81 pi integral_0^2 1 dx Apply the fundamental theorem of calculus. The antiderivative of x^2 is x^3/3: = (32 pi)/5+(-6 pi x^3)|_0^2+81 pi integral_0^2 1 dx Evaluate the antiderivative at the limits and subtract. (-6 pi x^3)|_0^2 = (-6 pi 2^3)-(-6 pi 0^3) = -48 pi: = -(208 pi)/5+81 pi integral_0^2 1 dx Apply the fundamental theorem of calculus. The antiderivative of 1 is x: = -(208 pi)/5+81 pi x|_0^2 Evaluate the antiderivative at the limits and subtract. 81 pi x|_0^2 = 81 pi 2-81 pi 0 = 162 pi: Answer: | | = (602 pi)/5 =~378.25
Let's take the total amount of students and divide it by the amount of people that can be seated on each bus.
241/36 = 6.6944444444444444
Now, you can't have 2/3 of a bus, so round up to 7.
They should rent 7 buses.
241 / 36 = 6 + 25/36 .....but....since we can't take a"partial" bus.....we'll need 7
CPhill is right. We are here to help.
Divide 56 by 2 and you get 28, so the number you are looking for is 28.
28, half of 56 is 28
That's what we're here for.......!!!!
Oh, I didn't mean to sound rude? I don't have an issue right now... but I struggle, so I'll let you know if I need help, if you want. 😊
Welome aboard, TC......!!!!!!
