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(-9/7)+1/3u=-3/2 = u=-((9/14))

It is Geometry. And yes. I do understand it, it is only difficult to comprehend.

Hmmm............. Maybe the "The Wrong Fate"

\(-4=(-4)/2-4\)

\(-4=(-2)-4\)

\(-4=-6\)

\(FALSE\)

\(-4>-6\)

Thanks @DragonSlayer554! Well, she's going to run off into the woods (she broke a serious rule) with a dude named Xavier and a girl named Libby, so I'm thinking of naming it "Together Alone", because they are together, but at the same time they're alone... IDK, I'm horrible at naming novels. XD

Nice idea!

Probably Hazel, or Ana, or Jewel, or Mary.

And the country can be The UNITED NOBLES OF AMERICA, OR the United Rulers, or the Land of Fate...

Tell me the name of your novel. Sounds interesting.

YAY!!!!!!!!!

Thanks for your help! I appreciate it! I will definitely check it out. Thanks so much!

Yeah, you can check out CliffsNotes, they're pretty good.

My bad weekends ALWAYS start good, but the next day it becomes HORRIBLE, and my good weekends are vice versa! LOL!!!
 

And mine is a good one! I fear that mine would be a bad weekend!

Ok. Thanks. 

I want to know (in advance, because I am in this after-school program for Honor students, called HYPE Los Angeles) how to do functions and stuff like those on a graph please. I am confused, and until Tuesday next week, I will start learning a little, and I want to get prepared.

Those are pretty wide-ranging topics, DS.......I doubt that anyone could cover all the info associated with each one on a forum like this.....

Maybe you had some specific questions???

Thanks, my friend! I am starting to understand. I am a seventh grader, and I don't have sufficient knowledge about this...

If cosθ = 1/4    we need to find the sinθ

So we have

cos^2θ + sin^2θ  = 1

[1/4]^2 + sin^2θ  = 1

1/16  + sin^2θ = 1

sin^2θ   = 1 -1/16   = 15/16     take the square root of both sides

sinθ  = ± √15 / 4       since θ  is in quad IV....the sine will be negative here

And tan(θ/2) = [ sinθ ] / [1  + cosθ]  = [ - √15 / 4] /  [1 + 1/4]  =

[ - √15 / 4] / [ 5/4]   =    [ - √15 / 4]  * [ 4 / 5]   = [ -4√15] / [20]   =  -√15 / 5

This is the exact value.....!!!

Note...since θ  is in the 4th quadrant, θ/2 will lie in the second quadrant.....and the tangent will be negative there.......just as we found...!!!!

Slopes: Ex. y=3x-8

Slope is in bold.

Function: Ex. f(x)=14x²+9

Function is italicized.

Domain: Ex. f(x)=3x²+6 {1,5,25}

Domain is underlined.

Once again, the domain of a function contains all of the possible input values that you can use — every number that can be put into the formula or equation and get a real answer.

Thanks for the answer, but can you put in more details since I have never done this before? Thanks!

Well, slopes are m in the y=mx+b formula (or the "Slope-Intercept" formula)

Functions are just about the same. Ex. f(x)=3x+27

Domains... Domains are a bit different. I am going to source CliffsNotes here. Ahem..."The domain of a function contains all of the possible input values that you can use — every number that can be put into the formula or equation and get a real answer."

If this is not what you are asking, please let me know. Thank you! :D

You were on the right track, rarinstraw  [I gave you 5 pts].....

Note that rarinstraw was correct......the slope of QA = -4/5

So...the slope between A and Q  = -4/5...and we need to solve this :

[-7 - y] / [8 - 3]  = - 4/5     cross-multply

5[-7-y]  = -4 [ 8 - 3]       simplify

-35 - 5y  = -4 [5]

-35 - 5y  = -20    add 35 to both sides

-5y = 15     divide both sides by -5

y = -3   ...just as rarinstraw found ....!!!!

These guys have posted worse ones! This is only one of those many questions!

 Two particles are separated by a distance of 0.3525977 m. Charge 1 has a charge of 0.0000764 C. Particle 2 has a charge of 0.0000745. What is the force between them?

Use the firmula: F=[k. Q. q] / r^2

F=[8.99 X 10^9 X .0000764 X .0000745] / .3525977^2

F=411.58 newtons-the force between the two charged particles.

A funny short conversation!

i know its way late but it would help others the answer is 50.07

thank you! yes it was -3 :))))

nope, that ain't me. Ans thnx, you too!

Cool pic, Emma....that isn't you, is it???

Whatever....have a good weekend, too......