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Who deleted my answer?

Well, the answer is obviously 2.5

Use the calculator next time!

Time taken = distance/speed, so time saved here = 8/16 - 8/18 hours or (8/16 - 8/18)*60 minutes (≈3.3 minutes)

Hey, be nice. Sometimes people don't know things. 

(q-5)(q-6) using the FOIL method.

First: q*q=q²

Outside: q*(-6)=-6q

Inside: (-5)*q=-5q

Last: (-5)*(-6)

q²-6q-5q+30

q²-11q+30

\((q-5)(q-6)\)

\(F.O.I.L.\)

F - First Times First \((q\times q)\)

O - Outside Times Outside \((q\times[-6])\)

I - Inside Times Inside \(([-5]\times q)\)

L - Last Times Last \(([-5]\times[-6])\)

When you do the \(F.O.I.L.\) method for this expression, you get :

\({q}^{2}-6q-5q+30\)

Now combine like terms

\({q}^{2}-11q+30\)

x² - 9x + 10 can be factored as (x - 1)*(x + 10) so the side lengths will be x-1 (= 12 in²) and x+10 (=23in²)

The height of an equilateral triangle is sqrt(3)/2 times the side length.

The area is given by half base times height so Area = (1/2)*8*(8*sqrt(3)/2) = 16*sqrt(3)

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A colony of bacteria is grown so that the population increases exponential with time. At the end of 3 hours there are 10,000 bacteria. At the end of 5 hours there are 40,000 bacteria. How many bacteria were present intially

40,000 /10,000=4x increase in bacterial count in 5-3=2 hours, therefore the exponential rate of inrease is=sqrt(4)=2 - 1 =1 X 100=100%.

Since the population doubles every hour, we therefore have in 3 hours:

10,000 / (2^3) =1,250 The initial population of bacterial colony.

I asume you mean \({x}^{2}+9x-10\), so I will go with that.

\({x}^{2}+9x-10\)

Subsitute \(x\) for 13.

\({13}^{2}+9\times13-10\)

\(169+9\times13-10\)

\(169+117-10\)

\(286-10\)

\(276\)

2.5

x² + 7x - 8 → (x - 1)(x + 8)

As written there is nothing to solve!  What do you want to do - find the value of t that makes r(t) = 0, or what?

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Wait... Nope! 17/200 = 0.085

Maybe I should use the calculator! :P

.34

Divide by -3 on both sides.

x<-4

Do it as follows:

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Does m have to be a positive integer?

It's called: USE THE CALCULATOR!!!!

12/45= 4/15 by dividing both the numerator and the denominator by 3