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TO find the area of the triangle, we use this formula

bh / 2

10 + 9 = 9 + 10

10 + 9 = 19

9 + 10 = 19

DONT ASK SIMPLE QUESTIONS!!!

WE ARE NOT DUMB!!!

6 + 5 + 5 = 650

Two Possible Answers:

Answer 1:

6 4 5 + 5 = 650

Place a line on the top left corner of the + to make it become a 4.

Answer 2:

6 + 5 + 5 ≠ 650

Stroke the = with a line to make it become a ≠.

  HELLO I STARTED COLLEGE LAST YEAR FOR THE FIRST TIME I AND WAS EXCITING BUT EXTREMLY DIFFERENT I HAVE VERY LITTLE COMPUTER SKILLS IT WAS SORT OF DISCOURAGING BUT NOT SERIOUS ALL I HAD TO DO WAS ASK QUESTIONS SOMEONE WAS ALWAYS AVAILABLE.MY GOAL IS TO RETURN BACK WITH FULL CONFIDENCE THAT I WILL SUCCESSFULLY COMPLETE COMMUNITY COLLEGE AND ADVANCE TO 4YR MORGAN STATE IS MY DESTANY TO A BRIGHT FUTURE.BE POSSITIVE ASK QUESTIONS UNTIL YOU GET THE RIGHT ANSWERS PACE YOURSELF AND DO NOT OVERWELM YOURSELF WITH UNNESSISSARY STRESS AND BEFORE YOU KNOW IT YOU WILL BE WALKING THE STAGE TO RECEIVE YOUR REWARD AND PERHAPS LAND THE DREAM JOB YOU HAVE ALWAYS WANTED. BEST WISHES TO THOSE WHO START TO FINISH.

Thanks Will, Heureka and Chris,

You have all given great answers :)

-7c+2=16

-7c=16-2

-7c=14

7c=-14

how many 7 go into 14

2 ;)

c=-2

so the way the other guest set it out was wrong

take it from me 

im a maths teacher

How many ways are there to put 6 toys in 3 boxes if the toys are not distinguishable but the boxes are?

The only relevant thing is how many toys go into each box :)

I get

See image below:

.

If the rectangle's corners are labelled HIJK in clockwise sequence, say, then HJ and IK are both diagonals, so we'd have:

x = 2x - 7 so that x = 7.

If the two runners started together and d**k runs slower until he got half hour behind Rick  and then D**k decided to suddenly speed up then it will take him less than 30 minutes to catch up to where Rick is now.

If D**k was travelling at     x km/hour   and at that pace he is a half hour behind Rick, then he will have 0.5x km till he gets to where Rick is.

So D**k needs to go faster than (18+0.5x) km in 2 hours

that is D**k needs to run faster than           (9+0.25x) km/hour

We need more information if you want to work our what x is.

Let's simplify the left side of the equal-sign:

\(c+3c = 4c\)

Combined;

\(4c=16\)

\(\frac{4c}{4} = c = \frac{16}{4} = 4\)

I have assumed that the reason why D**k is behind is that he started the race later than Rick.

Maybe he he had to start later for a penaly or maybe he just could not find his sports shoos idk.

Anyway I have assumed that he has been running at 12km/hour all the way.

I think Chris made different assumptions to me.

I think he assumed that they started together and so far D**k has just been running slowly.   

Ummm    maybe I should think about it his way - that is a harder question from the one I answered.  ://

That 27 is an error - I thought I had fixed it.

18 divided by 1.5 is definitely 12

I wish we could edit our posts   

Rick is in first place 18 km from the finish.

D**k is 30 minutes behind Rick  

If Rick averages 9 km an hour, how fast does D**k have to average to win?

Hi Chris, maybe you did b**w a fuse LOL

As Chris said, Rick will run 18 km at 9km/hour so that will take him 2 hours.  

D**k is a half hour behind.

It will take him 0.5 hours to get to where Rick was then he has to finish in under 1.5 hours in order to catch up to Rick.

So D**k will need to run the 18km in 1.5 hours   

18 divided by 1.5 = 27km/hour  

So D**k will need to be running fast than an average of 12 km/hour to win the race. 

THANK YOU ALAN

Lunch is not teaching

Therefore 350 mins

C. 0.912

If you're interested why:

'What is the probability that a student who studied for the exam saw an increase in their exam grade?'

From the question we're only interested in students who studied so we only need to worry about the 'studied' column.

Next we need to know what percentage (probability) of students who studied saw an increase.

So we simply divide the number of students who studied and saw an increase (0.52) by the total number of students who studied (0.57).

0.52 / 0.57 = 0.912280...

n - 35,000 = 42,000

+ 35,000 to both sides

n = 42,000 + 35,000

Solve

n = 77,000

Cos(45)= 1/sqrt(2), sin(30)=1/2, you can solve for these values by using properties of 45/45/90 and 30/60/90 triangles, it also helps to remember this- if you go all the way around the unit circle you'll only find 5 values. These values are- 0,1,1/2, sqrt(2)/2, and sqrt(3)/2. If you can remember that cos(x) is always equal to your x value on the units circle and sin(x) is always equal to the Y value on the unit circle, you should be able to derive every other trigonametric ratio. If I know sin(x) and cos(x) at any value of x, I can find tan(x) by dividing sin(x) by cos(x), and in much the same way I can find values for cosecant, secant, and cotangent. 

(a + 4b)/4 = (2a + b)/3 find the value a:b

Csc (x) is simply the inverse of sin(x) such that Csc(x)= 1/(sin(x)). If I know for instance that the value of sin(x) at some value x is equal to 1/2, I can use some basic algebra to find that Csc(x) at that point is equal to the value 2. 

\(\frac{{(xy)}^{3}}{{xy}^{3}}\)

\(\frac{{x}^{3}{y}^{3}}{{xy}^{3}}\)

\({x}^{2}{y}^{0}\)

\({x}^{2}\times1\)

\({x}^{2}\)

\(\sqrt{81\times4}\)

\(\sqrt{324}\)

\(\sqrt{9\times9\times9\times9}\)

\(9\times9\)

\(18\)

What is XLIV as a number=44