All Answers 358468 Answers

Thanks man!

15=10-x/4   subtract 10 from both sides

5  = -x/4      multiply both sides by  4

20  = -x      multiply through by -1

-20   = x

(a/7)+(5/7)=(2/7)     multiply through by 7

a + 5   = 2       subtract 5 from both sides

a =  -3

I think you mean 11 gal /min

So......

50gal / 11 gal/min    = 4,54 min   

And   .54min  = .54*60  =  about 32 seconds  .....so.....

It takes about 4 min 32 seconds to fill the bath

-6k(7k – 9) = 0  set each factor to 0

-6k = 0   divide by -6 on each side

k = 0

7k - 9  = 0     add 9 to both sides

7k = 9           divide both sides by 7

k = 9/7

So.....k=0    or  k  = 9/7

We can solve this with the following system

a(2)^2  + b(2) + c = 23

a(4)^2 + b(4) + c = 55

a(10)^2 + b(10) + c  = 247      simplifying, we have

4a + 2b + c  = 23            (1)

16a + 4b + c = 55           (2)

100a + 10b + c   = 247     (3)

Subtract (1) from (2)    and  (2) from (3)    ...and we get the following system

12a + 2b  =   32

84a + 6b  =  192       these simplify to

6a + b = 16    →    b =  16 - 6a    (4)

28a + 2b  = 64        (5)

Substitute   (4) into (5)

28a + 2[16 - 6a] = 64   simplify

28a + 32 - 12a  = 64

16a + 32 = 64    subtract 32 from both sides

16a  = 32      divide both sides by 16

a = 2

And using (4)  .....

  b =  16 - 6(2)  = 16 - 12  = 4

And using (1) ......

4(2) + 2(4) + c = 23

8 + 8 + c = 23

16 + c = 23

So    c  = 7

And our cost function is :

c(x)  = 2x^2 + 4x + 7       and the cost to produce 8 widgets is

c(8)  = 2(8)^2 + 4(8) + 7   =   2*64 + 32 + 7  =  128 + 39  = $ 167

Two examples

\(\frac{4}{2}\)

Take the reciprocal of the number in the denominator and multiply the two numbers

\(4\times\frac{1}{2}\)

\(\frac{4}{2}\)

\(2\)

\(\frac{\frac{1}{2}}{\frac{2}{3}}\)

Take the reciprocal of the number in the denominator and multiply the two numbers

\(\frac{1}{2}\times \frac{3}{2}\)

\(\frac{3}{4}\)

Help!!!!

If you know the base and the height of the parallelogram, you can calculate the area: \(A=b\times h\)

If you know the lengths of adjacent sides and one of the angeles, you can calculate the area: \(A=absinC;\) where where \(a\) and \(b\) are adjacent sides and \(C\) is the given angle.

Company ABC produces widgets. They have found that the cost,  c (x), of making x widgets is a quadratic function in terms of x. The company also discovered that it costs $23 to produce 2 widgets, $55 to produce 4 widgets, and $247 to produce 10 widgets. What is the total cost of producing 8 widgets?

=3 (x-1) (x+2)

Solve for x:
(2 (x-4))/5 = 1/2

Multiply both sides of (2 (x-4))/5 = 1/2 by 5/2:
((5×2 (x-4))/(2))/(5) = (5/2)/2

(5/2)/2 = 5/(2×2):
(5×2 (x-4))/(2×5) = 5/(2×2)

(5×2 (x-4))/(2×5) = (2×5)/(2×5)×(x-4) = x-4:
x-4 = 5/(2×2)

2×2  =  4:
x-4 = 5/4

Add 4 to both sides:
x+(4-4) = 5/4+4

4-4 = 0:
x = 5/4+4

Put 5/4+4 over the common denominator 4. 5/4+4  =  5/4+(4×4)/4:
x = 5/4+(4×4)/4

4×4  =  16:
x = 5/4+16/4

5/4+16/4  =  (5+16)/4:
x = (5+16)/4

5+16 = 21:
Answer: |  x = 21/4

Hello guest!

Two cylindrical containers are shown. Container A has a radius r and a height of h and holds a maximum of 100 ounces of water. Container B has a radius of 4r and a height of 12h. What is the maximum amount of water that Container B can hold?

Can I translate please?

Zwei zylindrische Behälter sind gezeigt. Container A hat einen Radius r und eine Höhe von h und hält maximal 100 Liter Wasser. Behälter B hat einen Radius von 4r und eine Höhe von 12h. Was ist die maximale Menge an Wasser, die Container B halten kann?

V_A = pi r² h

V_B = pi (4r)² * (12h)

Value equation

100 ounces / pi r² h = x / pi (4r)² * (12h)

x = 100 ounces)* pi * 16r² * 12h / pi * r² * h

x = 100 ounces * 16 * 12

x = 19 200 ounces

Ton B can hold 19 200 ounces water.

Greeting asinus :- )

 !

same way you normally round to the nth but to the millionth

Hello Guest!

A small bar of gold is a rectangular prism that measures 40 millimeters by 25 millimeters by 2 millimeters. One cubic millimeter of gold weighs about 0.0005 ounce. Find the volume in cubic millimeters and the weight in ounces of this small gold bar. What is the answer?

I'm so free.

Ein kleinerGoldbarren ist ein rechteckiges Prisma, das 40 Millimeter um 25 Millimeter

um 2 Millimeter misst. Ein Kubikmillimeter Gold wiegt etwa 0,0005 Unzen. Finden Sie das Volumen in Kubikmillimeter und das Gewicht in Unzen dieser kleinen Goldbarren .

V = abc = 40 * 25 * 2 mm³ = 2 000 mm³ = 2 cm²

Value equation

1 mm³ / 0.0005 ounce = 2 000 mm³ / x

x = 2000mm³ * 0.0005 ounce / 1 mm³

x = 1 ounce

The gold bullion is valued at 2 cm².

The gold bar weighs 1 ounce.

Greeting asinus :- )

 !

Does it count if its non or spaced out equally?

(angel choir) 

Thanks man!

Try this:

(3x - 3) (x + 2)  =

3(x - 1) (x + 2)

a^2 * b^3  = 108      this is true for a = 2 and b = 3

So  2a  + 3b =  2(2) + 3(3)  =  4 + 9   = 13

Its stands for living

lolz !

thank you Alfred E Neuman  :)