For 'B' it is not a perfectly elastic collision between the ball and the concrete.... some of the energy is lost in making a sound (air vibrations) some of the enrgy is lost in vibrations in the concrete, some of the nergy is lost in deformation of the ball AND the concrete...even though they may spring back to the original shape, this deformation results in heat in the ball and the concrete, lastly , thee is AIR friction to which the ball loses energy...this results in a minute heating of th air and the ball.
OK I'll try not to forget that and to put it in my next topic
No,
\(\pi + \pi = \tau\)
can i have some too please ?
That is fine EJ,
It would just be better if you explain that in your question because otherwise a person might spend time explaining it to you and not understaning that you do not need it explained. Maybe they would rather be do something else.
I already have the answers, that's just some "brain food"
Do you already know the answers EJ ?
Is this intended as a challenge question or do you seriously want help?
And, jeez, just cool down, it's not like it's the zombie apocolipse!
but, -4 is NOT greater than 1!!!
So is 00 because enything to the power of 0, equals 1, but 0 to the power of anything, equals 0.
So it equals 1 and 0 but you have to give out one scalar, you can't give out two scalars.
3x+7=x/2
\(3x+7=\frac{x}{2}\\ 2(3x+7)=2(\frac{x}{2})\\ 6x+14=x\\ 6x+14-x=x-x\\ 5x+14=0\\ 5x+14-14=0-14\\ 5x=-14\\ x=\frac{-14}{5}\\ x=-2\frac{4}{5}\\\)
THAT IS COMPLETLY RONG!!!!!!!!!!!!!!!!!!!!!!!!!!
THEY WERE TALKING ABOUT A FUNCTION!!!!!!!!!!!!!!!
yup, it's \(\aleph_0.\)
this is the output:
Hi, there!
I was just trying to give out some simple HTML.
This is MWizzard's physics question. It is not answered yet
61104
\(4k - 6 = -2k - 16 - 2 \\ 4k - 6 = -2k - 18 \quad | \, + 18 \\ 4k + 12 = -2k \quad | \, +2k \\ 6k + 12 = 0 \quad | \, -12 \\ 6k = -12 \quad | \, ÷ 6 \\ \therefore k = -2\)
Yup, it's a y.
