A gene isn't always "fixed" but has many forms. These forms are called "alleles". You may have a gene or genes for blue eyes that you inherited from, let us say, your mother. But the form of your gene(s) and your mother gene(s) for blue eyes maybe quite different, despite the fact they both give rise to blue eyes.
alleles are a type of gene
A vampire?
W*F?
after number type "^" and power you want to use. For example 2^2 is 2 to the 2nd power.
Usually by reducing them ...like example: sqt 8 = sqrt(4*2) = 2 sqrt2 or sqrt128 = sqrt(64*2) = 8sqrt2 etc
Divide the numerator (top number) by the denominator (bottom number).
1030
30.53 sq units
1/8 = HV
sqrt 2 / sqrt 3 if you mean 3 (sqrt8) / 3sqrt12
if you mean the CUBE ROOT OF 8 AND 12
cube root 8 = 2 cube root 12 = cube root 12
2 / cuberoot12 =.87358
We need to find the proportionality constant, k. So we have...
D = kT where D is the distance and T is the time
90 = K9 divide both sides by 9
10 = k
So...in 5 hours, we have
D = 10*5 = 50 (kilometers)
oh never mind
50. I am not a robot.
No, he/she still has to give you the number of years. Can't do much without that.
radius is 9mm, since it is 2 times less than diameter... circumference is diameter*pi so 18*pi mm. approx. 56,52 mm , but if you need exact answer leave the one with pi
The diameter is double the radius so the radius is 9. To figure out the circumefrence you multiply the diameter by pi so you should get 56.548. Your welcome
Aahhhh.... thanx for the clarification, Guest......but I still need the number of years...unless there is a standard .
every X coordinate, your graph will go up by 1/2 y coordinate instead of 2.
For instance, y=2x is a graph which has constant slope of 2, while y=x/2 is graph which has constant slope of 1/2. You can use any graphing program to see the difference for yourself
The answer of this question is
The radius is 56.52 millimeters.
The circumference is 56.52 millimeters.
If a line has LESS SLOPE, it is like a hill with less slope....it will become closer to flat ...or less steep
ElectricPavlov:
You got the formula right for the FV of ordinary annuity. However, he/she wants the FV of an "annuity due", which basically means that the annuity payments are made at the BEGINNING of the period instead of at the END of the period. As a result, your formula needs slight adjustment to account for that, namely: after the FV is obtained, you have to multiply it by [1 + i ] to give the FV of the " annuity due".
there are three 1/3 2/3 3/3
3/3 is 1
aren't* and k
