When the polynomial f(x) is divided by x3 - 2, the quotient and remainder are x2 + 4x - 1 and x, respectively. Determine the value f(3).
Sorry I have repaired my first answer, Heureka is right, 3^3 does equal 27 Thanks Heureka :)
\(\frac{f(x)}{x^3-2}=x^2+4x-1+\frac{x}{x^3-2}\\ f(x)=(x^3-2)[x^2+4x-1+\frac{x}{x^3-2}]\\ f(3)=(3^3-2)[3^2+4*3-1+\frac{3}{3^3-2}]\\ f(3)=(25)[9+12-1+\frac{3}{25}]\\ f(3)=(25)[20+\frac{3}{25}]\\ f(3)=[500+3]\\ f(3)=503\)
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