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thx because i was having problems reading one of the answers of one question on the forum. The person who wrote the answer used this word and i was like 'what is that?' xD

What is  .308 as a fraction?       308/1000     =      77/250 

3/4 = 0.75 = 75%

pie is not a number, you eat it. Or do you mean pi?

pi approximately equals 3.1415926535897932384626433 (I recited this when I was little because I was bored XD)

pi is \(\frac{circumference}{diameter}\)

It means "the other way round" or "meaning reversed".

You have to give 2 equations to solve 2 variables.

So, could you give the other equation too?

Webcalc won't solve this.  The only real number solution is derived numerically below:

.

Golden Ratio could be \(\varphi = 1.618 \)

OR

\(\varphi_1 = 0.618 \)

You can divide the (n+1)th term by the n th term in Fibonacci Sequence to get closer and closer approximation of \(\varphi \)

by using larger and larger values of n

-375° = -15° = 345° 

Hello Guest,

the answer is 188.4

32022/39806  x 100%  = 80.45 %

Agree with Melody.... ACELLERATION is a CHANGE in VELOCITY (over time).... all your problem has given is a constant velocity.

The train needs to be SLOWING (negative acceleration) or SPEEDING UP (positive acceleration) OR going around a curve.

f(x) / (x-2)    =   some polynomial ,let's call it P,  plus  a remainder of 17.

                    = ( P   + 17)

so f(x)          = (P   +17) (x-2)

so f(2)          = (P + 17) ( 2-2)       =  0

All well and good, but a generation is genearally considered to be 20 - 25 years.

In breeding always happens. If you go back enough generations you and I would most likely be related.

I don't get the relevance.  I'm not saying that it is not relevant I am just missing the logic :/

It's not important to the maths logic anyway :))

I selected 30 because that gives room for inbreeding (gross thought but it probably happpened)

I'd go for a new generation closer to every 20 years but we can do it your way. :)

\(Let\;\;\\y=2^{3333}\\ logy=log2^{3333}\\ logy=3333log2\\ logy\approx1003.332976\\ 10^{logy}\approx10^{1003.332976}\\ y\approx 10^{0.332976}\times 10^{1003}\\ y\approx 2.152662771\times 10^{1003}\\ \)

When the polynomial f(x) is divided by x3 - 2, the quotient and remainder are x2 + 4x - 1 and x, respectively. Determine the value f(3).

Sorry I have repaired my first answer, Heureka is right, 3^3 does equal 27    Thanks Heureka  :)

\(\frac{f(x)}{x^3-2}=x^2+4x-1+\frac{x}{x^3-2}\\ f(x)=(x^3-2)[x^2+4x-1+\frac{x}{x^3-2}]\\ f(3)=(3^3-2)[3^2+4*3-1+\frac{3}{3^3-2}]\\ f(3)=(25)[9+12-1+\frac{3}{25}]\\ f(3)=(25)[20+\frac{3}{25}]\\ f(3)=[500+3]\\ f(3)=503\)

When the polynomial f(x) is divided by x - 2, the remainder is 17. Determine the value f(2).

This might help

When the polynomial f(x) is divided by x3 - 2, the quotient and remainder are x2 + 4x - 1 and x, respectively. Determine the value f(3).

\(\begin{array}{rcll} \dfrac{f(x)}{x^3-2} &=& x^2+4x-1+\dfrac{x}{x^3-2} \qquad | \qquad \cdot (x^3-2) \\ f(x) &=& (x^2+4x-1) \cdot (x^3-2)+ x \\ f(3) &=& (3\cdot 3+4\cdot 3-1)\cdot(3\cdot 3 \cdot 3 - 2) + 3 \\ f(3) &=& (9+12-1)\cdot (27-2) +3 \\ f(3) &=& 20\cdot 25 +3 \\ f(3) &=& 500 +3 \\ \mathbf{f(3)} &\mathbf{=}& \mathbf{503} \end{array}\)

Again you have not given enough information.  Not even for a 'guess' answer.

You need to say something like.

The train went from stopped to 90mph in 5 minutes or something - you need a time frame.  :)