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Do you have a question that goes with that ratio?

35 ft  x   12 inches/ft  =               inches

you can do the crunching.....

I think you've missed a minus sign in number 1 Max:  x = -64

yes

youve never done this kind of problems before?

1.\(\sqrt[6]{64}=2\)

2.\(\sqrt[3]{128}=2^{\frac{7}{3}}\)

3.\(\sqrt[10]{1024}=2\)

4. Wow here comes the hardest question

\(\sqrt[7]{\frac{-8\sqrt2}{2187}}=\frac{((-2)^\frac{3}{7})(2^\frac{1}{14})}{3}=-\frac{\sqrt2}{3}\)

Hi Max, I just wanted to show you this code      

\frac{d}{dx}f(x) =\displaystyle\lim_{h\rightarrow0}\; \frac{f(x)-f(x+h)}{h}

\(\frac{d}{dx}f(x) =\displaystyle\lim_{h\rightarrow0}\; \frac{f(x)-f(x+h)}{h}\)

Solve by substitution:

By considering the 3rd equation,

z=1+x

By considering the 2nd equation,

y=x+z=x+1+x=2x+1

Substitute these into the 1st equation,

x+(2x+1)+(1+x)=10

4x+2=10

2x+1=5

x=2

y = 2(2)+1 = 5

z = 1+(2) = 3

I love substitution method more, it's faster.

I assume you mean x^2-x=0

\(x^2-x=0\)Divide by x

\(x-1=0\)

\(x = 1\)

\(-8\sqrt{\frac{2}{2187}}\)

=\(\frac{-8\sqrt2}{27\sqrt3}\)

=\(-\frac{2^32^{\frac{1}{2}}}{3^33^{\frac{1}{2}}}\)

=\(-\frac{2^{\frac{7}{2}}}{3^{\frac{7}{2}}}\)

\(-(\frac{2}{3})^{\frac{7}{2}}\)

So, I came across a interesting question, that is, to simplify:sqrt(31+12*sqrt(3)) We are told to show the answer in a+b*sqrt(3) format, so i wonder how is it possible to simplify to this extent.

\(simplify\;\;\;\sqrt{31+12\sqrt3}\\ \mbox{We need to express }31+12\sqrt3 \mbox{ as a perfect square.}\\ (a+b)^2=a^2+2ab+b^2\\ 2ab=12\sqrt3\\ ab=6\sqrt3\\ Let\;\;b=c\sqrt3\\ (a+c\sqrt3)^2=a^2+2ac\sqrt3+(c\sqrt3)^2=31+12\sqrt3\\ (a+c\sqrt3)^2=a^2+2ac\sqrt3+3c^2\qquad=31+12\sqrt3\\ ac=6\\ a^2+3c^2=31\\ Try\;\;a=2\;\; and\;\; c=3\\ ac=6\;\; tick\\ a^2+3c^2=2^2+3*3^2=4+27=31\;\;tick\\ so\\ (2+3\sqrt3)^2=31+12\sqrt3\\ \sqrt{31+12\sqrt3}=\sqrt{(2+3\sqrt3)^2}=2+3\sqrt3 \)

-2x=2

\(x=\frac{2}{-2}=-1\)

\(\sqrt{31+12\sqrt3}\)

=\(\sqrt{2^2+12\sqrt3+(3\sqrt3)^2}\)

=\(\sqrt{(2+3\sqrt3)^2}\)

=\(2+3\sqrt3\)

Hey! That is not a mathematical question!

Type '√' in your calculator and type that number, press '=' or 'EXE' and if you get a whole number, that number is a perfect square.

\(\frac{100%}{10%}=10\)

\(\frac{a}{2}+\frac{2}{3}=\frac{5}{6}\)

\(3a+4=5\)

\(3a=1\)

\(a=\frac{1}{3}\)

\(\left (\sqrt{42n}\right )^9 \)

= \(\sqrt{406671383849472n^9}\)

= \(3111696n^4\sqrt{42n}\)

\(\frac{sin23.48}{cos49.27}\)

is not equal to -37.7. it equals 0.611

\(2^6=2\times2\times2\times2\times2\times2=4\times4\times4=64\)

\(\frac{d}{dx}f(x) = lim_{h\rightarrow0} \frac{f(x)-f(x+h)}{h}\)

If there is a point (a,b) on a Cartesian coordinate plane and a corresponding point (r,θ)......

r = \(\sqrt{a^2+b^2}\)

θ = \(atan \frac{b}{a}\)

Where atan is inverse tangent.