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thanks

1cm=10mm

4.5cm x 10 =45mm

1mm=5m the sacle, so

45mm x 5m=225 m

thanks

the ratio at a school is 9:11 if the school has 400 students how many are girls

9 / (9 + 11)  x 400 =180 are boys

400 - 180 =220 are girls

it is boys to girls

\(\text{use the quadratic formula :} \\x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

here is the roots:

When you give a ratio of 9:11, you must specify whether it is girls to boys, or boys to girls.

\(176-96=80\\ 96:80\\ 6:5\)

Answer:  6:5

3.14159265359 but people only use 3.14

 t-3.4=7.6 add 3.4 to both sides

t=7.6 + 3.4

t=11

what is 3c^4 times 6c^7

3c^4 x 6c^7=18c^11

A triangle has side lengths 10, 15, and 7. Is the triangle acute, obtuse, or right,

The description of a triangle as right, acute or obtuse is based on its internal ANGLES!.

When the SIDES of the triangle are given, then the triangle is described as Right, Equilateral, Isosceles and Scalene.

In your question, the triangle would be classified as "Scalene".

Go online and see your graph here:

https://www.desmos.com/calculator

whats -3x_> 36

-3x > 36 divide both sides by -3 and reverse

x < -12

tan-^1 ( -1)= -45 degrees

cos^2 45deg=1/2

Thanks guest, i'm just practicing using Latex  :)

ok now I will try it using the inverse method.

\( \begin{bmatrix} 1 &-1 \\ 2&1 \end{bmatrix} \begin{bmatrix}x  \\y \end{bmatrix}= \begin{bmatrix} -1 \\ 7 \end{bmatrix}\\ \frac{1}{1*1--1*2} \begin{bmatrix} 1 && 1 \\ -2 &&1 \end{bmatrix} \begin{bmatrix} 1 &-1 \\ 2&1 \end{bmatrix} \begin{bmatrix}x  \\y \end{bmatrix}= \frac{1}{1*1--1*2} \begin{bmatrix} 1 && 1 \\ -2 &&1 \end{bmatrix} \begin{bmatrix} -1 \\ 7 \end{bmatrix}\\~\\ \frac{1}{3} \begin{bmatrix} 1+2 && -1+1 \\ -2+2 &&2+1 \end{bmatrix} \begin{bmatrix}x  \\y \end{bmatrix}= \frac{1}{3} \begin{bmatrix} -1+7 \\ 2+7 \end{bmatrix}\\~\\ \frac{1}{3} \begin{bmatrix} 3 &&0 \\ 0 &&3 \end{bmatrix} \begin{bmatrix}x  \\y \end{bmatrix}= \frac{1}{3} \begin{bmatrix} 6 \\ 9 \end{bmatrix}\\~\\ \begin{bmatrix} 1 &&0 \\ 0 &&1 \end{bmatrix} \begin{bmatrix}x  \\y \end{bmatrix}= \begin{bmatrix} 2 \\ 3 \end{bmatrix}\\~\\ \begin{bmatrix}x  \\y \end{bmatrix}= \begin{bmatrix} 2 \\ 3 \end{bmatrix}\\~\\ x=2 \qquad and \qquad y=3 \)

If you are confused try watching this video and the one that follows it.

So, what is the question? If she saves $1, $2, $4.........just for ten days, she will have saved $1,023.00, which should be enough to buy a new bike.

Just divide: Miles travelled/Gallons used. That would give you MPH.

The easiest way to deal with very large calculations such as yours is to use a "Math Package", such as Mathematica, Maple.....etc. They also have very extensive graphing capabilities. In the meantime, if you wish to do large calculations such as these, go online and download a free calculator called "HiPER CALC". Just google it and you will see it.

For graphing only, you can try this online calculator: "The Desmos graphing calculator" Again just google it and will you see it.

Hi undertheshade,

Welcome to Web2.0calc  forum     

y=x+1

1x-1y=-1

y=7-2x

2x+1y=7

\(\begin{bmatrix} 1 &-1 \\ 2&1 \end{bmatrix} \begin{bmatrix}x \\y \end{bmatrix}= \begin{bmatrix} -1 \\ 7 \end{bmatrix}\\ \)

There are different ways to do this - I shall use reduced row escelon form.

\(\begin{bmatrix} 1 &-1\:\:|\:-1\\ 2&1\:|\:7 \end{bmatrix} \\~\\\mbox{Top row (row 1) }\times 2\\~\\ \begin{bmatrix} 2 &-2\:\:|\:-2\\ 2&1\:|\:7 \end{bmatrix}\\~\\ \mbox{row 2 - row 1}\\~\\ \begin{bmatrix} 2 &-2\:\:|\:-2\\ 0&3\:|\:9 \end{bmatrix}\\~\\ \mbox{row 1 times 3}\\ \mbox{row 2 times 2} \\~\\ \begin{bmatrix} 6 &-6\:\:|\:-6\\ 0&6\:|\:18 \end{bmatrix}\\~\\ \mbox{row 1 plus row 2} \\~\\ \begin{bmatrix} 6 &0\:\:|\:12\\ 0&6\:|\:18 \end{bmatrix}\\~\\ \mbox{row 1 divided by 6}\\\mbox{row 2 divided by 6} \\~\\ \begin{bmatrix} 1 &0\:\:|\:2\\ 0&1\:|\:3 \end{bmatrix}\\~\\ x=2 \qquad y=3\)

first re-arrange to get

x - y  = -1  and

2x + y  = 7

Now form your matrices

1   -1         x      =     -1 

2     1        y              7   

Now pre-multiply both sides by the inverse of  matrix    1 -1  

                                                                                       2   1           and just read off  for x  and y .

(Assumes that you know how to find the inverse of a 2 x 2 matrix.)  

FV=PV[1 + R]^N

FV =185,000[1+.041]^30

FV=185,000 x 1.041^30

FV=185,000 x 3.3382732

FV=617,580.56 pounds

X^2*x^3 → x^5

x^5 = 243 means x = 3