Let N be the shorter side of Sam's TV screen
Then the longer side will be (4N/3)
Then, by the Pythagorean Theorem, we can solve this equation for N
N^2 + (4N/3)^2 = 55^2
And N = 33 in And the longer side = (4 *33 / 3) = 44 in
So.......the dimensions of Sam's set = 33 in x 44 in
Let M be the shorter side of Pete's TV screen
Then, the longer side will be (16M/9)
And, using the same logic we have
M^2 + (16M/9)^2 = 55^2 and M≈26.964 in And the longer side ≈ (16 * 26.964 / 9) ≈ 47.936 in
So.....the dimensions of Pete's set = 26.964 in x 47.936 in
The area of Sam's screen = (33 * 44)in^2 = 1452 in ^2
And the area of Pete's screen = ( 26.964 * 47.936) in^2 = 1292.55 in^2
So....in terms of area.........Sam has the bigger screen