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1/2(12)(23)=(6)(23)=138

Let's convert the yards and feet to inches

7 yards = 7 * 36 = 252 inches     2 feet = 24 inches

So, I'm assuming that the pot is shaped like a cylinder?? If so, the "formula for the volume of a cylinder is

V = pi * r^2 * h         and since the diameter is 252 inches, the radius = 126 inches

So, using 3.14 for "pi," we have

V = 3.14 * (152 in)^2 * (24) =  1741117.44 in³

and the volume of each ice cube is 2in x 2in x 2in = 8 in³

And dividing the pot's volume by the volume of each ice cube we have

1741117.44 in³ / 8 in³ = 217639.68 ≈ 217640 ice cubes   

You'd better hurry, though before they melt.....then, we'll have to figure how many gallons of water the pot holds!!

No, this sum has a finite limit:

$$\sum_{k=2}^{\inf}(\frac{-3}{7})^k=\frac{9}{70}$$

See the following figure;

 In this respect it is more like the infinite series 1 + 1/2 + 1/4 + 1/8 etc. which has the finite sum of 2. In other words it is a geometric series, the sum to infinity of which is given by:

sum = a0/(1-r) where a0 is the first term [(-3/7)² here] and r [= (-3/7)] is the ratio between successive terms.  Because r is less than 1, successive terms get smaller, r^∞→0, and the sum converges to a finite value.

$${\mathtt{sum}} = {\frac{{{\mathtt{\,-\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{7}}}}\right)}^{{\mathtt{2}}}}{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{7}}}}\right)\right)}} \Rightarrow {\mathtt{sum}} = {\mathtt{0.128\: \!571\: \!428\: \!571\: \!428\: \!6}}$$

$${\frac{{\mathtt{9}}}{{\mathtt{70}}}} = {\mathtt{0.128\: \!571\: \!428\: \!571\: \!428\: \!6}}$$

Just noticed this is a very old unanswered question!!

We need to use the sin for this

sin θ = opp / hyp

sin 42 = h / 33     where h is the height of the kite

33*sin 42 = h = 22.08 ft

Ah! tan(x)≥sin(x)

Edit.

Melody is correct below!  The correct result is given when tan(x)-sin(x)>=0. i.e. when 0≤x<pi/2 and pi≤x<3pi/2 

To get the length of the other diagonal, DB, we'll use this "formula" to find the measure of angles DAC and CAB :

Cos θ  =   [u(dot)v] /( llull  * llvll)          Where u and v are vectors and

[u(dot)v] - the dot product of u and v  and

llull = length of u and

llvll = length of v

So, taking AD and AC as vectors

AD =<5.4, 39.7>  AC = <40.6, 40.2>    AD(dot)AC = 1815.18

llADll = 40    llACll = 57.1

cos^-1 (1815.18)/(40*57.1) = m< DAC =37.37

And again, taking AB and AC as vectors

AB = <40.6 ,0>  AC <40.6, 42.7>          AB(dot)AC = 1648.36

llABll = 40.6    llACll = 57.1     

cos^-1 (1648.36)/(40.6*57.1) = m< CAB = 43.8

m< DAB = m< DAC + m< CAB = 37.37 + 44.7 = 82.07

And using the Law of Cosines, DB = SQRT (40^2 + 40.6^2 - 2(40)(40.6)cos(82.07)) = 52.92 ≈ 53

And that's close enough for me!!

I don't know

5+5=10

10=5+5

EG=36

1 second= 1s

1 millisecond = 0.001s

1 microsecond = 0.000001s

1 nanosecond = 0.000000001s

$${\frac{{\mathtt{0.301}}}{{\mathtt{0.003\: \!8}}}} = {\frac{{\mathtt{1\,505}}}{{\mathtt{19}}}} = {\mathtt{79.210\: \!526\: \!315\: \!789\: \!473\: \!7}}$$

15*5*2

15*5=75

75*2=150

2pi*32=$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{32}} = {\mathtt{201.061\: \!929\: \!829\: \!746\: \!767\: \!3}}$$

no, since to make x^3 you need x*x*x

y=0

7-12y=7

7-0=7

12y=0

y=0

-6*2/3+32/9

-4+3+5/9

-1+5/9

-4/9

I think that's how it works

What's the value of N, if there isn't any then it is just N+4

-33+24=-9 simple addition

0.9 270/300=0.9

Hey SpawnAngel,

I think you misread the question,

if I confess and my friend does not I will get 20 years and he will get 0.

The other way around I get 0 and he gets 20.

Also it's not a matter of confessing or not confessing.

The question is how big the odds of your friend confessing should be in order for you to choose to not confess or confess.

Have another look at it. It is not as difficult as it may seem, however it does require a little calculation 

numerator/denominator

the smallest common denominator is 20 so A) 26/20 and B) 35/20

infinity since it is infinite, just like 1+2+4+8+16...

2 2/3 = 2 and 10/15 = 1 and 25/15

1 4/5 = 1 and 12/15

1 25/15 - 1 12/15 = 13/15

6x10=60 10-4=6

What? How? 1+2=3 You must have pressed 2+2 or 2x2 by accident