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do 1000-number= into your calculator

\(\quad y(5x^2+2x)-x(2y-6y^2)\\ =5x^2y+2xy-2xy+6xy^2\\ =5x^2y+6xy^2\)

\(\dfrac{\sqrt3}{\sqrt{15}}\\ =\dfrac{\sqrt3}{\sqrt3\times\sqrt5}\\ =\dfrac{1}{\sqrt5}\\ =\dfrac{\sqrt5}{5}\)

Suppose the ratio of Lev's age to Mina's age is 1:2 and the ratio of Mina's age to Naomi's age is 3:4.
What is the ratio of Lev's age to Naomi's age? Give your answer in simplest form.

The easiest way to understand this problem is to assign some ages to the various names in the question:

So, Let us assume that Lev =3 years old, and therefore Mina would be =6 years old. Or 1:2 ratio.

If Mina is 6, then Naomi' s age will be =8 years. Or a 3:4 ratio.

Therefore Lev's age to Naomi's age would be= 3/8, or 3:8 ratio. And this ratio will hold true whatever ages you give them according to the ratios given. Example: If Lev is 12, then Mina will be 24, and Naomi will be 32 years old. So, 12:32 =3:8...... and so on.

f(x) = 2x + 2(-x) = 2x - 2x = 0.

\(+5-(-9)+(+3)\\ =5 + 9 + 3\\ = 17\)

Number = 100C7 = 16007560800. :)

Use the calculator on this site!! The calculator is really useful!!

\(7\left(\left(18-6\right)-6\right)\\ = 7(12-6)\\ = 7(6)\\ =42\)

???

This is an uncommon and rather involved calculation:

1) Convert the two interest rates, 4% and 5% from semi-annual comp. to monthly comp.

4% = 3.96706838956     and   5% =4.94869855817.

2) Calculate the monthly payment of the mortgage amortized over 30 years. And that comes to:

= $1,334.23.

3) Find the balance of the mortgage at the end of 5 years, which comes to=$229,404.06

4) Find the PV of the anove balance in 3 PLUS the PV of the remaining 30 payments of $1,334.23 each at the sale price of 4%.

5) The totals in 4 above come to: $207,778.33 + $38,046.27 =$245,824.60, which is the sale price of this mortgage @ 4% comp. semi- annually.

200 /900 =2/9=~22%

80 /4 =20 Km per hour.

Leap year =366 days

 95 13/18= 95°43´20´´

V = lwd   Volume = length * width * depth

We know its length and depth so we must solve for width:

w= V / ld

Now, we can fill in values:

w= 2808 ft^3 / (18 ft * 12 ft)

w= 2808 ft^3 / 216 ft^2

w = 13 ft

Solve the following system:
{x+y+z = 6 | (equation 1)
2 x-y+z = 3 | (equation 2)
3 x-z = 0 | (equation 3)
Swap equation 1 with equation 3:
{3 x+0 y-z = 0 | (equation 1)
2 x-y+z = 3 | (equation 2)
x+y+z = 6 | (equation 3)
Subtract 2/3 × (equation 1) from equation 2:
{3 x+0 y-z = 0 | (equation 1)
0 x-y+(5 z)/3 = 3 | (equation 2)
x+y+z = 6 | (equation 3)
Multiply equation 2 by 3:
{3 x+0 y-z = 0 | (equation 1)
0 x-3 y+5 z = 9 | (equation 2)
x+y+z = 6 | (equation 3)
Subtract 1/3 × (equation 1) from equation 3:
{3 x+0 y-z = 0 | (equation 1)
0 x-3 y+5 z = 9 | (equation 2)
0 x+y+(4 z)/3 = 6 | (equation 3)
Multiply equation 3 by 3:
{3 x+0 y-z = 0 | (equation 1)
0 x-3 y+5 z = 9 | (equation 2)
0 x+3 y+4 z = 18 | (equation 3)
Add equation 2 to equation 3:
{3 x+0 y-z = 0 | (equation 1)
0 x-3 y+5 z = 9 | (equation 2)
0 x+0 y+9 z = 27 | (equation 3)
Divide equation 3 by 9:
{3 x+0 y-z = 0 | (equation 1)
0 x-3 y+5 z = 9 | (equation 2)
0 x+0 y+z = 3 | (equation 3)
Subtract 5 × (equation 3) from equation 2:
{3 x+0 y-z = 0 | (equation 1)
0 x-3 y+0 z = -6 | (equation 2)
0 x+0 y+z = 3 | (equation 3)
Divide equation 2 by -3:
{3 x+0 y-z = 0 | (equation 1)
0 x+y+0 z = 2 | (equation 2)
0 x+0 y+z = 3 | (equation 3)
Add equation 3 to equation 1:
{3 x+0 y+0 z = 3 | (equation 1)
0 x+y+0 z = 2 | (equation 2)
0 x+0 y+z = 3 | (equation 3)
Divide equation 1 by 3:
{x+0 y+0 z = 1 | (equation 1)
0 x+y+0 z = 2 | (equation 2)
0 x+0 y+z = 3 | (equation 3)
Collect results:
Answer: |x = 1                     y = 2                   z = 3

If you subtract the 4 from both sides to solve for x, you get -x = 3. To finish solving for x, x must be positive (you don't want negative x, you want x), so you multiply both sides by -1 to get x = -3. A negative times a negative is a positive: -1 * -x = x. If you have negative one set of negative x units, you have x units in all.

6xy + 12xz + 9yz = 3xyz.               Original equation
2xy + 4xz + 3yz = xyz                    Factor out the common 3's
2xy = xyz - 4xz - 3yz                     Put all z'on same side of the equation
2xy = z(xy-4x-3y)                          Factor out the common z's
z = 2xy / (xy-4x-3y)                       Divide for z

Solve for x:
x^2+(x+1)^2 = 25

Expand out terms of the left hand side:
2 x^2+2 x+1 = 25

Divide both sides by 2:
x^2+x+1/2 = 25/2

Subtract 1/2 from both sides:
x^2+x = 12

Add 1/4 to both sides:
x^2+x+1/4 = 49/4

Write the left hand side as a square:
(x+1/2)^2 = 49/4

Take the square root of both sides:
x+1/2 = 7/2 or x+1/2 = -7/2

Subtract 1/2 from both sides:
x = 3 or x+1/2 = -7/2

Subtract 1/2 from both sides:
Answer: |x = 3 The shorter leg.     3+1=4 The longer leg.     Hypotenuse=5

I figured it out myself, it's 

5x^2y-6xy^2

divide 160 by 5 and then multiply that by 4

4(5x-3)=28

Distribute the 4

20x-12=28

Isolate the variable

20x=40

Divide both sides by 20

x=2