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Alan,

How did you go from the second line to the third line?

That sign is the absolute value. If a number is positive, you turn it into a positive number. If the number is negative, you ignore the minus sign in the number.

Examples: |8.3|=8.3,|-5|=5.

Here's an alternative approach:

.

-0.072/0.08

-(.72/.08)

answer=  -0.9

Working out

1.4-0.4(t-3.1)=5.8

1.4-0.4t+1.24+5.8

t+1.24=5.8

t=8.8-1.24

t=4.56

t=4.56

Why do you need help fast?  Are you doing a test or something?

Well there you go, we both learned something.   

If you sign up your get higher priority with answerers.

I know you were answered quicklly this time but it doesn'ty always work that way. :)

It depends on the inflation rate and the country you live in. In the US, the inflation rate for that period was 313%. So, a $5,000 car in 1976 dollars would be worth:$5,000 x 3.13 =$15,650 in 2012 dollars.

I know nothing about cars, so I don't know how it compares to today's cars.

the perimeter of a pentagon is made up of 5 consecutive integers. the perimeter is 460. what is the are consecutive numbers?

let the integers be

a,a+1,a+2,a+3,a+4

so

5a+10=460

now solve it :)

Google

Googolplex

it becomes a postive because (-)*(-)=+

Thank you so much. It makes sense now

Thanks guest - no other answer read the question properly.

For a Perpetuity to work the interest paid must equal the regular payment so that  the principal never decreases.

you just have to be a little careful about when the first payment begins. ...

Thanks Guest

I learned from your answer   :)

I will just rewrite your answer in LaTex

\(\displaystyle\lim_{x\rightarrow \infty} \;\sqrt{9x^2+x}-3x\\ =\displaystyle\lim_{x\rightarrow \infty} \;\frac{\sqrt{9x^2+x}-3x}{1}\times\frac{\sqrt{9x^2+x}+3x}{\sqrt{9x^2+x}+3x}\\ =\displaystyle\lim_{x\rightarrow \infty} \;\frac{(9x^2+x)-9x^2}{\sqrt{9x^2+x}+3x}\\ =\displaystyle\lim_{x\rightarrow \infty} \;\frac{x}{\sqrt{9x^2+x}+3x}\\ =\displaystyle\lim_{x\rightarrow \infty} \;\frac{x\div x}{(\sqrt{9x^2+x}+3x)\div x}\\ =\displaystyle\lim_{x\rightarrow \infty} \;\frac{1}{\sqrt{\frac{9x^2+x}{x^2}}+3}\\ =\displaystyle\lim_{x\rightarrow \infty} \;\frac{1}{\sqrt{9+\frac{1}{x}}+3}\\ =\frac{1}{\sqrt{9+0}+3}\\ =3+3\\ =6 \)

Thanks Ginger,

That is really fabulous. I am as pleased as punch.  Or maybe that is a pleased as Ale :))

That is a fabulous tribute.    

I am very pleased that LancelotLink did not take his personal chef with him.  

Your Daiquiri creation tastes divine, it has exactly the right amount of imperial minims ! :)

Thanks guest, I just want to play to  :)

Suppose the ratio of Lev's age to Mina's age is 1:2 and the ratio of Mina's age to Naomi's age is 3:4.
What is the ratio of Lev's age to Naomi's age? Give your answer in simplest form.

So the ratio of Lev to Naomi is   3:8

When six basketball players are about to have a​ free-throw competition, they often draw names out of a hat to randomly select the order in which they shoot. What is the probability that they shoot free throws in alphabetical​ order? Assume each player has a different name

There are 6! ways to order 6 people.  Only one of those will be in order A to z

so the probability is     1/6!    =    1 / 720

Thanks

Find the following limit:
lim_(x->∞) (sqrt(9 x^2+x)-3 x)

sqrt(9 x^2+x)-3 x = (3 x+sqrt(9 x^2+x))/(3 x+sqrt(9 x^2+x)) (sqrt(9 x^2+x)-3 x) = x/(3 x+sqrt(9 x^2+x)):
lim_(x->∞) x/(3 x+sqrt(9 x^2+x))

Write x/(3 x+sqrt(9 x^2+x)) as 1/(3+sqrt(9 x^2+x)/x):
lim_(x->∞) 1/(3+sqrt(9 x^2+x)/x)

Using the reciprocal rule, write lim_(x->∞) 1/(3+sqrt(9 x^2+x)/x) as 1/(lim_(x->∞) (3+sqrt(9 x^2+x)/x)):
1/(lim_(x->∞) (3+sqrt(9 x^2+x)/x))

lim_(x->∞) (3+sqrt(9 x^2+x)/x) = lim_(x->∞) 3+lim_(x->∞) sqrt(9 x^2+x)/x:
1/(lim_(x->∞) 3+lim_(x->∞) sqrt(9 x^2+x)/x)

Since 3 is constant, lim_(x->∞) 3 = 3:
1/(3+lim_(x->∞) sqrt(9 x^2+x)/x)

Simplify radicals, sqrt(9 x^2+x)/x = sqrt((9 x^2+x)/x^2):
1/(3+lim_(x->∞) sqrt((9 x^2+x)/x^2))

Using the power rule, write lim_(x->∞) sqrt((9 x^2+x)/x^2) as sqrt(lim_(x->∞) (9 x^2+x)/x^2):
1/(3+sqrt(lim_(x->∞) (9 x^2+x)/x^2))

The leading term in the denominator of (9 x^2+x)/x^2 is x^2. Divide the numerator and denominator by this:
1/(3+sqrt(lim_(x->∞) (9+1/x)/1))

The expression 1/x tends to zero as x approaches ∞:
1/(3+sqrt(9))

1/(3+sqrt(9)) = 1/6:
Answer: |1/6

Simplify the following:
-6-6 abs(9-4)

9-4 = 5:
-6-6 abs(5)

Since 5>=0, then abs(5) = 5:
-6-6×5

-6×5 = -30:
-30-6

-6-30 = -36:
Answer: |-36

447.553348775

for a problem like this( limit to infinity) plug in a random nember and determine whether its a positive or negative. the awnser for this problem is positve infinity since (((9(1)^2)+(1))^1/2)-3(1) is positive