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it should be -8.

20-12= 8 because we are taking 12 away from 20

In this case: 12-20 = -8 because we are taking 20 away from 12.

2x+2y=36

    y+1=x+3     |-1

        y=x+2

2x+2(x+2)=36

   2x+2x+4=36    |-4

             4x=32   |:4

               x=8

      2*8+2y=36

       16+2y=36    |-16

             2y=20    |:2

               y=10

(1)    x+3y=17

(2)     y+2=2x+3         |-2

             y=2x+1

        x+3(2x+1)=17

             x+6x+3=17   |-3

                     7x=14  |:7

                       x=2

                 2+3y=17   |-2

                     3y=15  |:3

                       y=5

A) Given that y=(x^2 +7)^(1/2) find dy/dx

Let   x^2 + 7  = m

And we can write

dy/dx =  dy/dm * dm/dx

So we have

y = m^(1/2)          taking the derivative of this = 

dy/dm  =  (1/2)m^(-1/2)

And 

dm/dx =  2x

So...puting this all together, we have

dy/dx =  dy/dm * dm/dx =   (1/2)m^(-1/2) * 2x     =   (1/2)(x^2 + 7)^(-1/2) * 2x =    x * (x^2 + 7)^(-1/2)

Hello

my was a cool 

Find the derivative of the following via implicit differentiation:
d/dx(y) = d/dx(sqrt(7+x^2))
The derivative of y is y'(x):
y'(x) = d/dx(sqrt(7+x^2))
Using the chain rule, d/dx(sqrt(x^2+7)) = ( dsqrt(u))/( du) 0, where u = x^2+7 and ( d)/( du)(sqrt(u)) = 1/(2 sqrt(u)):
y'(x) = (d/dx(7+x^2))/(2 sqrt(7+x^2))
Differentiate the sum term by term:
y'(x) = d/dx(7)+d/dx(x^2)/(2 sqrt(7+x^2))
The derivative of 7 is zero:
y'(x) = (d/dx(x^2)+0)/(2 sqrt(7+x^2))
Simplify the expression:
y'(x) = (d/dx(x^2))/(2 sqrt(7+x^2))
Use the power rule, d/dx(x^n) = n x^(n-1), where n = 2: d/dx(x^2) = 2 x:
y'(x) = 2 x/(2 sqrt(7+x^2))
Simplify the expression:
y'(x) = x/sqrt(7+x^2)
Expand the left hand side:
Answer: |y'(x) = x/sqrt(7+x^2)

Mine was cool.

Example ....if we wanted to evaluate :

log₂ 8   

Key in :

log(8, 2)      and hit "enter"

....or    4.5 quadrillion

.....or   four quadrillion five hundred trillion.

Hmmmmm......seems you left something off of your question.

5 + 3H =  just that = 5 + 3H     cannot do anything more with it.....sorry!

Can't do any more with this.....it's fully simplified....

Yep.........it's rational

Example →    .66666.......   =   2/3

As a couple of examples:

.33333.......

let 'x' = .3333333.....

then 10x = 3.33333.....

subtract 'x' fro 10x        3.3333.....

                                   -   .3333....

                                  ____________

9x     =                          3.0     Solve for 'x'

x = 3/9 = 1/3

Another one:

.8989898989.......

let 'x' = .8989.....

then 100x = 89.8989.....         (not that we have to use 100x in this example because there are TWO repeating digits)

then 100x - x        

                           89.8989........

                         -     .8989.......

                        ____________

99x =                  89.                            Solve for 'x'

x = 89/99

Do you have SPECIFIC examples of which you need help ???

Yes but the quesrion isnt 8/1 its 1/8

4,500,000,000,000,000

sqrt40 = ksqrt10

sqrt(4 x 10) = ksqrt10

2sqrt10= ksqrt10

2=k

(1 / 8) ^-2/3   

Notice this fact......we can invert the fraction and make the exponent positive....so we have

(8 / 1) ^2/3  =

(8) ^2/3   =

(8 ^1/3 ) ^{2    =}

( ∛ 8 ) ²   =

(2) ²  = 

4

Thanks!! 

~Reni

-1 3/4 = -1.75

1/9 x 100% =   1 divided by 9 times 100 = 11.11%

Note   √24   is  less than 5   because √25   = 5

So √26  is  more than 5

So....three  possibilities are     [ 4 + 99/100] ,   5  and  [5 + 1/100]

First, there are FOUR significant digits in your question, so the sci notation should have 4 significant digits too:

1.325 x 10^(-2)