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5/6 = 0.8333333333333333

9/1022 = 0.0088062622309198

0.0088062622309198+0.8333333333333333 = 0.8421395955642531

Therefor, your answer would be: 

0.8421395955642531

~Reni

We can use the tangentto solve this.......let h be the building height......and we have

tan (32) = h / 88    multiply both sides by 88

88 * tan (32)  = h  ≈  55 ft.

4(x+2/3)-6    distribute the  "4"  over the terms in the parentheses

4x + 8/3  - 6     =       write "6"   as "18/3"

4x + 8/3 - 18/3  =

4x - 10/3

See if this helps :

http://www.chemteam.info/SigFigs/SigFigRules.html

7/25 = 7 divided by 25     using a calculator results in 0.28

Let T be the time [in hours]  for Roberto to travel.......and let {T - 1]  be the time for his parents to travel......and since theyboth travel the same distance when his parents catch up, we have

Roberto's Rate * His Travel Time =  Parent's Rate * Their Travel Time

30 * T  =  45  * [ T - 1]     simplify

30T = 45T - 45   add 45 to both sides, subtract 30T from both sides

45 = 15T      divide both sides by 15

3 = T     →  it will take his parents [T - 1] =  [3 - 1]  =  2 hours to catch him

hi Isabelle,

It is only a technicality, many people do not use brackes very well.

Here is the question:

Find (f-g)(x) when f(x)=2x+6/3x and g(x)=(sqrt x)-8/3x

By convention this is what is REALLY presented.

\(f(x)=2x+\frac{6}{3}x \quad and \quad g(x)=\sqrt x-\frac{8}{3}x\)

This is how I would have interpreted the meaning

\(f(x)=2x+\frac{6x}{3} \quad and \quad g(x)=\sqrt x-\frac{8x}{3}\)

and this is how Max interpreted it

\(f(x)=\frac{2x+6}{3x} \quad and \quad g(x)=\frac{\sqrt{x} -8}{3x}\)

Do you see now what I meant and why brackets are so important    

Roberto's distance at time 't'   =  30 + 30 t     (the 30 is the headstart he got by going one hour earlier)

His parents distance is                45 t

When are they equal?

30 + 30t = 45t

30 = 15t

t = 2 hours after 12 o'clock     Roberto traveled 90 miles, his parents traveled  90 miles  (this will be 3 hours after Roberto leaves.....and only two hours after his parents leave)

The alphabet doesn't have any numbers, so there can be no 'best number of the alphabet' .

7/3  is   'Seven thirds'   is the same as  7 divided by 3   is the same as  2  1/3   is the same as 2.333333....

98/4kg = 24.5/kg

The number of hits is given by f(x)

The numbers of HITS are given as 4  12  14  27  42

f(x) = 4 = x-11    solve for 'x'   x = 15 PITCHES

f(x) = 12 = x-11                       x = 23 pitches

etc

etc......Then add all of the pitches....

Let 'x' be the integer

x+2 is the next integer

x+4 is the third integer

They all add to 126

x  +  x+2  +  x+4   = 126

3x +6 = 126

3x=120

x=40

Assuming that both diameters are in meters, we have

1 * 10^-6  +  1.45 * 10^-5   =

1 * 10^-6 + 14.5 * 10^-6  =

10^-6 [ 1 + 14.5]  = 

10^-6 [ 15.5]  =

10^-5 * 1.55   =

1.55 * 10^-5   meters

ab = 1      a + b = -4  →   b = -4 - a

Subbing the last equation into the first, we have

a[-4 - a]  = 1      simplify

-4a - a^2  = 1     rearrange

a^2 + 4a + 1  = 0      using the quadratic formula to solve, we have

a = √3 - 2      or    a =    -√3 - 2

Which means that b =    -4 - [ √3 - 2] =  -2 - √3     or   b =  -4 - [  -√3 - 2  ] =  √3 - 2

So

(a^2  - b) * (b^2 - a)  =  [ ( √3 - 2)^2  - ( -2 - √3) ] * [ ( -2 - √3)^2  - (√3 - 2) ]  =

[ 3 -4√3 + 4 + 2 + √3] *  [ 4 + 4√3 + 3 - √3 + 2]  =

[ 9 - 3√3] * [ 9 + 3√3 ]  =

81 - 27 = 

  =  54

Evaluating this when a =  -√3 - 2   and b =  √3 - 2    gives exactly the same result  as shown below

(a^2  - b) * (b^2 - a)  =  [ ( -√3 - 2)^2  - ( √3 - 2) ] * [ ( √3 - 2 )^2  - (-√3 - 2) ]  = 54

212

Cost for company C:  C  =  50.00 + 0.10m                  (where m represents the number of miles)

Cost for company A:   A  =  20.00 + 0.60m

When the cost for C < cost for A:

                         50.00 + 0.10m  <  20.00 + 0.60m

                                     -0.50m  <  -30.00

                                       0.50m  >  30.00

                                              m  >  60                     (If the mileage is greater tahn 60 miles) 

(x-1)^2-x^2 = -5      expand the expression in the parentheses

x^2 - 2x + 1 - x^2  = -5      simplify

-2x + 1   = -5      subtrtact 1 from each side

-2x = -6    divide both sides by -2

x = 3 

Starting with:  y  =  ¼(x - 6)²

First:  expand:  (x - 6)²     --->     (x - 6)²​  =  (x - 6)(x - 6)  =  x² - 12x + 36

Then:  multiply this answer by ¼     --->     ¼(x² - 12x + 36)  =  ¼(x²) + ¼(-12x) + ¼(36)  =  ¼x² - 3x + 9

It's ur dumb as f**k

I am going to assume that the snail is to climb a wall of 457 cm (not m).

The "trick" in this question is to realize that the snail will climb the last 10 cm without slipping back down 7 cm.

So, the snail will climb 347 cm at the rate of 3 cm per hour:  347 / 3  =  149  hours

      and, then, 1 more hour to get to the top:  150 hours.

69 is the answer

3 i think

Velocity includes a direction, speed doesn't.

For example, a velocity might be 35 meters per second north

   while the corresponding speed would be just 35 meters per second..

About 10 days or 100