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I was so busy answereing I forgot to say hello.

Welcome back to the fourm songoflight :))

Say everyone one in your class does a test.

You order the papers from best to worst.  

The mode is the score that happens the most often,  there might be no mode or one mode or any number of modes.

The median is the score on the paper that is right in the middle of the pile.  OR if there are 2 middle papers than the median is the average of the 2 middle scores.

Do you know the Hey Didile Diddle nursery rhyme ?

Here is a statistical version of it.

Hey diddle diddle,

The median's the middle,

You add and divide for the mean,

The mode's the one you see the most and the range is inbetween     :))

Just jump forward man, thats what i did and im alive

Uhhhhhh 42

What is a "potens" meant to be?

Wow!. Is this a "Challenge Question" or what??.

First, the person or the teacher who posed this question doesn't seem to be familiar with modern TVM formulas!!

There are two questions here:

1) What is the amount of $M that she can withdraw each month and still allow her to save $80,000 as a down payment on her house?.

We know she deposits $4,500 in her savings account that earns 4.5% comp. monthly.

Will have to find the FV of these 72 payments (6 years) using this common formula:

FV=P{[1 + R]^N - 1/ R}=FV OF $1 PER PERIOD.

Plugging all the numbers in and crunching them, we get:

FV=$372,555.59. But we know she wants to keep $80,000 of this for her down payment. So we have:

$372,555.59 - $80,000 =$292,555.59 the balance in savings account that she can spend.

Plugging this into the above TVM formula, we can calculate her monthly withdrawal from her savings account. And this monthly amount comes to:$3,533.70. This is the amount of $M in the question.

2) The balance in her savings account after depositing two payments of $4,500 each and withdrawing of two payments of $3,533.70 each will be:

$9,050.69 - $7,107.20=$1,943.48, using the same above TVM formula!!.

P.S. The two questions posed were answered in reverse, in order to determine the $M of her withrawals. Also, remember that her payments were made at the beginning of the month, which has been taken into account. All that mumbo-jumbo of R^72+R^71+R^70.........are totally unnecessary. And that is the END!!.

Hi Cubncad    

there are 16 mathematicians and 24 grad students. School will pay for 4 mathematicians and 5 graduate students to go. If the department has 16 mathematicians and 24 graduate students, how many different delegations are possible?

16C4  *  24C5 

ABC is a right angle triangle. D is the point on AB such that AD=3DB. AC=2DB and angle A=90.

Show that sinC=k/square root 20, where k is an interger. Write down the value of k.

\(\begin{array}{|rcll|} \hline DB &=& x \\ AD &=& 3x \\ AB &=& AD + DB\\ &=& 3x +x \\ &=& 4x\\\\ AC &=& 2DB \\ &=& 2x \\\\ hypotenuse &=& CB \\ CB^2 &=& AB^2+AC^2 \\ &=& (4x)^2+(2x)^2\\ &=& 16x^2+4x^2\\ &=& 20x^2 \\ CB &=& \sqrt{20x^2} \\ &=& x\cdot \sqrt{20}\\\\ \sin(C) &=& \frac {AB}{CB} \\ &=& \frac {4x}{x\cdot \sqrt{20}} \\ &=& \frac {\mathbf{4} } { \sqrt{20} } \\ \text{So the value of k is }\mathbf{4} \\ \hline \end{array} \)

determine the sum of all the multiples of 4 between 1 and 999

arithmetical sequence: \(sum = 4 + 8 + 12 + 16 + 20 + 24 + \dots+996\)

\(n = \frac{996}{4} = 249\)

\(\begin{array}{|rcll|} \hline sum &=& \frac{(a_1+a_n)\cdot n}{2} \\ &=& \frac{(4+996)\cdot 249}{2} \\ &=& \frac{1000\cdot 249}{2} \\ &=& 500 \cdot 249 \\ &=& 124500 \\ \hline \end{array}\)

Like so:

.

Use Pythagoras:   horizontal distance = sqrt(hypotenuse^2 - height^2)

.

4x+10=-26   Subtract 10 from both sides

4x = -36    Divide both sides by 4

x = -9

.

Look carefully at step 2.

2x^2- 6x+2=0 Divide all terms by 2:

x^2 - 3x + 1 = 0  Use the quadratic equation:

x1 = (3 + sqrt(3^2 - 4))/2 → 3/2 + sqrt(5)/2

x2 = (3 - sqrt(3^2 - 4))/2 → 3/2 - sqrt(5)/2

.

i(square root)2 , its i since it is an imaginary number since youre trying to find the square root of a negative number

Those are variables. How am I supposed to give you an answer?

There is no square root of a negative number, it's invalaid

What is the value of x if 2x/3=140. Please explain if able to.

2x/3=140 cross multiply

2x =140 x 3

2x = 420 divide both sides by 2

x =420 / 2

x = 210

what does e mean in 9e+10 mean?

"e" stands for "exponent". 9e+ 10 means=9 x 10^10

Let the consecutive numbers = n, n+1, n+2,

33[n+ n+1+ n+2] = n* (n+1)* (n+2), solve for n

Solve for n:
33 (3 n+3) = n (n+1) (n+2)

Expand out terms of the left hand side:
99 n+99 = n (n+1) (n+2)

Expand out terms of the right hand side:
99 n+99 = n^3+3 n^2+2 n

Subtract n^3+3 n^2+2 n from both sides:
-n^3-3 n^2+97 n+99 = 0

The left hand side factors into a product with four terms:
-((n-9) (n+1) (n+11)) = 0

Multiply both sides by -1:
(n-9) (n+1) (n+11) = 0

Split into three equations:
n-9 = 0 or n+1 = 0 or n+11 = 0

Add 9 to both sides:
n = 9 or n+1 = 0 or n+11 = 0

Subtract 1 from both sides:
n = 9 or n = -1 or n+11 = 0

Subtract 11 from both sides:
Answer: |n = 9         and 10          and 11

Hi thisismyname  :)

Your question is interesting :))

Suppose  b and c are positive integers.
When b^2 is written in base c, the result is 121_c. When c^2 is written in base b, the result is 71_b.
What is b+c?

\(b^2=121_c\\ b^2=1*c^2+2*c+1\\ b^2=c^2+2c+1\\ b^2=(c+1)^2\\ b=c+1\\~\\ c^2=71_b\\ c^2=7b+1\\ c^2=7(c+1)+1\\ c^2=7c+8\\ (c-8)(c+1)=0\\ c=8 \;\;or \;\;c=-1 \qquad \text{but c is positive so}\\ c=8\\~\\ b=8+1=9\\ so\\ b+c=17 \)

there might be a short cut so that you do not have to find both b and c seperately.....

I didn't notice one though.

lol being freaky and asking a math question isnt going to get u anywhere.19 is the answer. Yes im a girl. just so u wont ask iv ebeen asked five times today

The integers are 9, 10, and 11. The sum of these integers is 30. Their product is 990.

(9x10x11=990, 9+10+11=30 30x33=990)

A)  2,350,000 = 2^4 * 5^5 * 47

B) 2,350,000 / [3.14 .4/3] =561,305.73 ft^3

[561,305.73]^1/3 =82.49 feet - the radius od the Spaceship Venus.

4x4 is 16 so 16plus 10 is 26