Hello dayor!
what is the solution for 2x^2- 6x+2=0
\(2x^2-6x+2=0\)
\(a=2; \ b=-6; \ c = 2\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(\)\(x = {6 \pm \sqrt{36-4 \times 2 \times 2} \over 2 \times 2}\)
\(x= \frac{6 \pm \sqrt{20} }{4} \)
\(x= \frac {6 \pm 4.472135955}{4}\)
\(x_{1}=2.61803398875\)
\(x_{2}=0.38196601125\)
Greeting asinus :- ) 
!
\(\)
\(\)
.
