All Answers 358348 Answers

Do something / something.

Divisions = Fractions.

\(y = 1-\dfrac{\sec x}{\tan x} =1 - \sec x \cot x = 1- \dfrac{1}{\cos x \tan x}=1-\dfrac{1}{\sin x}\\ y'=(1-\dfrac{1}{\sin x})'=0-(\dfrac{\cos x}{\sin^2x})=-\dfrac{\cos x}{\sin^2x}\)

You can think about it like this:

754 - 175.5 = 754 - 175 - 0.5 = 579 - 0.5 = 578.5 :)

2(x) + 2(2)= 2(x+2)

a whole number and a fraction like 1 2/5

x/y

Divide by 3.14159265358979323846264338327

using prodcut or quoitent rule

y=x+1/(x^3+x-2) !!!

2(x+2)

Well at least we all agree now anyway :))

Ginger, I was looking for some hair dyes that could help you get the mix more consistently correct......

I don't think I achieved my goal but I did find this...

-2*(1+h)³=-2*(1+h)*(1+h)*(1+h)

               =-2*(1+h+h+h²)*(1+h)

               =-2*(1+2h+h²)*(1+h)

               =-2*(1+h+2h+2h²+h²+h³)

               =-2*(1+3h+3h²+h³)

               =-2-6h-6h²-2h³

with a calculator.   

Use the web2 calc on the home page :)

0*0=0

so

sqrt (0) = 0

There is a number of ways that this can be done.

If you are a junior student then

I suggest that you multiply   (1+h)(1+h)

then mulpiply the answer by (1+h)

then multply that answer by -2

2y^2+33x+15 using these methods: GCF, grouping, DOTS, AC method

This cannot be simplified or  factorized.  And since there is no equal sign it certainly cannot be solved

If you want more explanation then you just need to ask for it.    

Hi Trang17la,    

sketch the graph and state the range :

y=x+1

Fill in this table and then plot the points and join them together to make a graph

the domain is all possible x values and the range is all possible y values.

An algebra class has 6 students and 6 desks. For the sake of variety, students change the seating arrangement each day. How many days must pass before the class must repeat a seating arrangement? days must pass before a seating arrangement is repeated.

This is the same as asking how many ways are there to arrange 6 people in a line.

Person one has 6 positions to choose from, person 2 has 5 positions to choose from and so on.

Total number of arrangements = 6! = 720

Suppose the desks are arranged in rows of 3. How many seating arrangements are there that put Larry, Moe, & Curly in the front seats? There are seating arrangements that put them in the front seats.

There are 3! =6  ways of seating Larry, moe and curly in the front seats

and 

there it 3!=6 ways of seating the other 3 in the back seats.

so altogether there are  6*6=36 arrangements were L,M and C are in the front seats.

using prodcut or quoitent rule

y=x+1/x^3+x-2

this is the question that you have asked

\(y=x+\frac{1}{x^3}+x-2\\ y=x^{-3}+2x-2\\ y=3x^{-3}+2\\ \)

I assume that you intended a different question ??   I suggest that you learn how to use brackets !!!!!

Tell you what.

You can write your own calculator program and you can have the default as anything you want.   

Do you think that peole here should do your homework????

Do you think that people here should do your homework???

|-3x+1|-3>-1/9|-54|-18

- 54/9 - 18 = -24

abs(1 - 3x) -3 > -24