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3(x-4)-2(x+1)

=3x-12-2x-2

=x-14

(x+3)/12 = 2   |*12

       x+3 = 24  |-3

           x = 21

Yep

Hole in 1 for Zegroes :))

What is (7.3 x 105) + 2400000

Put it into the website calculator on the home page like this. .

(7.3*10^5)+2400000

Start by multiplying both sides by 12

3|-8| = 3×|-8|=3×8=24

- 19

2x^2+x+45=90

Let A (2,5) and B (6, -1). Find:

a) the equation of line AB

b) the length of the line perpendicular to AB

For b) I still need a point.

What is the temperature of the patient after 25 minutes (hint t = 25)

Presumably you're solving for y.

\(0=(2y-1)\times(8-y)\)

You have two chunks of numbers (each set of parentheses is one chunk), two values, which when multiplied equal 0. The only way this equation can make sense is if either

\((2y-1)=0\)

or else

\((8-y)=0\)

If neither of these values is 0, then there is no way to multiply the two values and get 0 as your answer. Therefore, there are two possible solutions to this equation. Either (2y-1)=0 or (8-y)=0

So you solve each of those two equations out for y, and that will give you the two values that y could equal.

\(\)

Determine the balance after 20 years in an account that had an initial investment of $25,000 at 5% interest, compounded continuously.

FV=$25,000 x e^(.05*20)

FV=$25,000 x 2.718281828...

FV=$67,957.05

I believe we're missing a few crucial variables in this problem buttt, I can tell you you'll be fifty years older than you are now.

It's just Square Root 121, which is eleven. 

Happy to help.

                                             3n + 8  =  20

Subtract 8 from both sides:     3n  =  12

Divide both sides by 3:               n  =  4

The formula is:  A  =  P(1 + r/n)^nt

A = final amount = ?

P = beginning amount = $3000.00

r = yearly rate, written as a decimal = 0.06

n = number of times per year that the rate is compounded = 1

t = number of years = 10

A  =  P(1 + r/n)^nt     --->     A  =  3000(1 + 0.06/1)^1·10     --->     A  =  $5372.54

The domain is the set of all numbers that are allowed to be used for x. 

Every number can be used, so the domain is the set of all real numbers.

Your mistake came in this:

"Then we get that x^2 = -1, and since this can never be true, there should be no real domain."

Instead of saying "there should be no real domain", you should have said "since this can never be true, there are no numbers that are eliminated". (You need to eliminate all the numbers that make the denominator zero; if no numbers make the denominator zero, none are eliminated.)

4(x^2+5)-10y

4x^2 + 20 - 10y

Arithmetic Series?  18, 15, 12, 9, 6, 3, 0, -3, -6, -9...........etc.

Common difference = -3

No there is not

Shoot I'm dumb.

We don't set it = 0

we set it to =/= 0

Solve for h:
h/3-4 ((2 h)/(3)-3) = (2 h)/(3)-6

Put each term in (2 h)/(3)-3 over the common denominator 3: (2 h)/(3)-3 = (2 h)/3-(9)/3:
h/3-4(2 h)/3-(9)/3 = (2 h)/(3)-6

(2 h)/3-(9)/3 = (2 h-9)/3:
h/3-4(2 h-9)/3 = (2 h)/(3)-6

h/3-(4 (2 h-9))/3 = (h-4 (2 h-9))/3:
(h-4 (2 h-9))/3 = (2 h)/(3)-6

-4 (2 h-9) = 36-8 h:
(h+36-8 h)/3 = (2 h)/(3)-6

h-8 h = -7 h:
(-7 h+36)/3 = (2 h)/(3)-6

Put each term in (2 h)/(3)-6 over the common denominator 3: (2 h)/(3)-6 = (2 h)/3-(18)/3:
(36-7 h)/3 = (2 h)/3-(18)/3

(2 h)/3-(18)/3 = (2 h-18)/3:
(36-7 h)/3 = (2 h-18)/3

Multiply both sides by 3:
36-7 h = 2 h-18

Subtract 2 h from both sides:
36+(-7 h-2 h) = (2 h-2 h)-18

-7 h-2 h = -9 h:
-9 h+36 = (2 h-2 h)-18

2 h-2 h = 0:
36-9 h = -18

Subtract 36 from both sides:
(36-36)-9 h = -18-36

36-36 = 0:
-9 h = -18-36

-18-36 = -54:
-9 h = -54

Divide both sides of -9 h = -54 by -9:
(-9 h)/(-9) = (-54)/(-9)

(-9)/(-9) = 1:
h = (-54)/(-9)

The gcd of -54 and -9 is -9, so (-54)/(-9) = (-9×6)/(-9×1) = (-9)/(-9)×6 = 6:
Answer: |h = 6