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Hi Heureka,

Your tree is very impressive!

What program did you use to draw it?  Can you draw one from left to right as well?

Try looking here.  It might help give you an idea of the concept.

http://www.mathsisfun.com/numbers/infinity.html

There are 12 inches in a foot so 3 inches is 3/12 of a foot = 1/4 feet = 0.25feet.

You can't do this unless all the units are the same.

so 3 inches is 0.25 of a foot.

$${\mathtt{124}}{\mathtt{\,\times\,}}{\mathtt{83}}{\mathtt{\,\times\,}}{\mathtt{0.25}} = {\mathtt{2\,573}}$$

so the answer is a volume of 2573 feet cubed

Have  a look at this page.  It will help.

http://www.mathsisfun.com/numbers/infinity.html

$$\begin{array}{rll}
2^{3.4}&=&2^{\frac{34}{10}}\\\\
&=&2^{\frac{17}{5}}\\\\
&=&\left(2^{17}\right)^{1/5}\\\\
&=&\sqrt[5]{2^{17}}\\\\
&=&\sqrt[5]{131072}
\end{array}$$

Let the speed of the train be "x"

Then the speed of the plane is five times as fast plus 50km/hr = 5x + 50

Remember that Distance/Rate  = Time

And the time the train travels = Its Distance Traveled/Its rate  = 600/x

And the time the airplane travels = Its Distance Traveled/Its rate = 3500/(5x + 50)

But the times are equal....so

600/x = 3500/(5x + 50)

The easiest way to solve this is to just to take the cross products and set them equal, i.e.,

600(5x + 50) = 3500x       Expanding the left side, we have

3000x + 30000 = 3500x    Subtract 3000x from both sides

30000 = 500x                    Divide by 500 on both sides

60 = x   And that's the rate of the train in km/hr

And the plane's rate is 5(60) + 50 = 350km/hr

Okay Lets do this:

Distance flown by the Airplane = 3500 Kilometers

Distance traveled by the train = 600 Kilometers

Lets make x the taken by the Airplane

Because of this, it would make sense that the time taken to travel 600 Kilometers is also x.

Now to find out the speed of the Airplane, the forumla is 

$${\frac{{\mathtt{3\,500}}}{{\mathtt{x}}}}$$

Now to find out the speed of the Train, the forumla is

$${\frac{{\mathtt{600}}}{{\mathtt{x}}}}$$

Now let us use what we already know.

$${\frac{{\mathtt{3\,500}}}{{\mathtt{X}}}} = {\mathtt{5}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{600}}}{{\mathtt{X}}}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{50}}$$

$${\frac{{\mathtt{3\,500}}}{{\mathtt{x}}}} = \left({\frac{{\mathtt{3\,000}}}{{\mathtt{x}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{50}}\right)$$

Now we need to eradicate the x

So we multiply x to both sides.

$${\mathtt{3\,500}} = {\mathtt{3\,000}}{\mathtt{\,\small\textbf+\,}}{\mathtt{50}}{\mathtt{\,\times\,}}{\mathtt{X}}$$

Now we need to use some basic algebra knowledge to solve this. Let us move x to one side and the numbers on the other. We will get

$${\mathtt{x}} = {\mathtt{10}}$$

Now, lets go back to what we know already know and substitute.

For the Plane:

$${\mathtt{SPEED}} = {\frac{{\mathtt{3\,500}}}{{\mathtt{X}}}}$$

$${\mathtt{SPEED}} = {\frac{{\mathtt{3\,500}}}{{\mathtt{10}}}}$$

$${\mathtt{SPEED}} = {\mathtt{350}}{KM}$$per hour

For the Train:

$${\mathtt{SPEED}} = {\frac{{\mathtt{600}}}{{\mathtt{X}}}}$$

$${\mathtt{SPEED}} = {\frac{{\mathtt{600}}}{{\mathtt{10}}}}$$

$${\mathtt{SPEED}} = {\mathtt{60}}{KM}$$ per hour.

There we go.

The Speed of the plane was 350KM per hour 

and the speed of the train was 60 Km per hour

Intensity = current (I)

Tension = Voltage (V)

Resistance (R)

Ohm's law says V = I*R

V = 16*2 volts

V = 32 volts

u are 16 yrs old now !

$$Do you mean $\sum_{k=1}^{25}(3k+\frac{1}{4})$?\\
\\
If so, then this can be written as $$3\sum_{k=1}^{25}k+\sum_{k=1}^{25}\frac{1}{4}$$\\\\
This becomes $$3*\frac{25(25+1)}{2}+25*\frac{1}{4}$$\\
$$ = 975+6\frac{1}{4}$$
$$ = 981\frac{1}{4}$$

Nah, I understand. However, generally when they ask a question like this, they are looking for a detailed answer. So they don't ask again, they can do it themselves

im sorry everyone mistakenly i missed out a part of the question heres th correct question ;

an aeroplane flies 3500km in the same time a train covers 600 km . if the speed of the aeroplane is 50km/hr more than five times the speed of the train . what are the speeds of the train and aeroplane ?

It is a good explanation Takahiro,

Thumbs up from me too

but it would have been better and easier if you had just added all the whole numbers first.

So you would have

$$2+1+3+2+4+\frac{1}{3}+\frac{3}{5}+\frac{1}{6}+\frac{3}{4}+\frac{2}{5}\\\\
\mbox{as you worked out the LCD (Lowest Common Denominator is 60)}\\\\
12+\frac{20}{60}+\frac{36}{60}+\frac{10}{60}+\frac{45}{60}+\frac{24}{60}\\\\
etc$$

I hope you don't mind me pointing this out - I am a compulsive teacher.  

That appears to be impossible, rosala

If the speed of the airplane is five times that of the train, it would travel 5 times as far in the same time

But 3500 / 600 = about 5.8 times as far

Thanks Takahiro, I have given you a thumbs up, but you are assuming a lot of pre knowledge.

Many children are not capable of changing fractions to decimals like you did.

WE need to teach the children.  

This could mean

1)  a detailed explaination of the hand method. or

2) a lesson on how to use the calcuator. 

PLUS 

you will find after you have been here for a while that you get sick doing fraction calculator questions for the children.  There are a multitude of them every day.  

The thread that i refered the person to is a Sticky Topic and is located in the bottom right of the page.(you should take a look at the thread too)

You can just tell them where it is if you want or you can give them the direct link if you prefer. OR you can do it your own way and not use the thread, it is up to you.

Cheers

Melody

Go to the home page

Make sure the calc is set to degrees, there is a toggle button in the bottom left corner.

and write in  (you don't need to use the buttons unless you want to, you can enter from you keyboard)

asin(9*sin(81)/11)   then hit enter

That should give you the answer that you need.

------------------------------------------

If you would rather press buttons it is

2nd sin (9*sin(81)/11) press enter (Ive heard the equal sign isn't working)

@@    Alan's graph is good but you need to read what I have written!

The equation of the y axis is x=0   (No matter what the y value is, the x will always be equal to 0)

So if you want to know what the y intercept is, you just substitute in x=0

y=0-0+10

the y intercept is 10

For questions of this form, the y intercept is the constant on the end.  But it is much better if you understand why. 

i think u should first write the correct question and then ask for the answer !

6 times you have exactly two tails: FFBB, FBFB, FBBF, BFFB, BFBF, BBFF

And the Probability is  $$6*\left(\dfrac{1}{2}\times\dfrac{1}{2}\times\dfrac{1}{2}\times\dfrac{1}{2} \right)$$

OK.......no prob

thanks CPhill !

What confused you??

Let the granddaughter's age be  "x"

Then, the grandfather's age = "10x"

And the difference in their ages is representsd by

10x - x = 54

So

9x = 54    Divide by 9

x = 6       That's the granddaughter's age

And the grandfather's age is 10x = !0(6) = 60

Quadrant:   I    II   III   IV

sin(x)         +    +    -     -

cos(x)         +    -    -     +

3. Quadrant  sin X< 0 and cos X <0

sorry CPhill i actully cant understand ur answer proplerly ! im getting a bit confused ?