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Is this really a question?

Hi Lisaseal,

Q26

well look at 0 to 3

13.6 apart

Incline = 2 degrees     that is uphill by 2 degrees

Azimuth = 76 degrees

so 

3  to 0 will be

13.6 apart

decline = 2 degrees     that is       Incline =  -2 degrees

Azimuth (compass direction) = 180+76 degrees = 256 degrees

Question 27

draw the triangle :)

sin76 = h / 13.6

h=13.6*sin76

13.6*sin(76) = 13.1960218773536

The horizontal distance is about 13.2 feet

I have a physics question if anybody can help me out.

At 1m away a politiction produces a sound intensity at 80 dB in a park without obstables.

Approx what is the sound intensity at 30 meters away? I'm considering using 1 over R formula,

however it doesn't give an answer in dB.

Sound I be using logarithms?

Formula:

\(\begin{array}{|rrcll|} \hline Let & I_1 &=& 80\ dB \\ Let & r_1 &=& 1\ m \\ Let & I_2 &=& ? \\ Let & r_2 &=& 30\ m \\\\ & I_2 &=& I_1 - 10 \cdot |~ \log( (\frac{d_1}{d_2})^2 ) ~| \qquad \text{ sound intensity }\\\\ & I_2 &=& 80\ dB - 10 \cdot |~\log( (\frac{1\ m}{30\ m})^2 )~| \\ & I_2 &=& 80\ dB - 10 \cdot |~\log( 0.00111111111 )~| \\ & I_2 &=& 80\ dB - 10 \cdot |~(-2.95424250944)~| \\ & I_2 &=& 80\ dB - 10 \cdot 2.95424250944 \\ & I_2 &=& 80\ dB - 29.5424250944 \\\\ & \mathbf{ I_2 } & \mathbf{ = } & \mathbf{ 50.4575749056\ dB } \\ \hline \end{array} \)

If you have one apple plus another five apples you get this   | plus | | | | | and so together there is | | | | | | witch equals six all together. Using this mecanism mentaly you could work out any multiplacation (adding/plusing) equasion :]

just build from there.

what is cot(A) if cos(A)=2/radical(13)

\(\begin{array}{|rcll|} \hline \cos(A)&=& \frac{2} { \sqrt{13} } \\\\ 2^2+x^2 &=& ( \sqrt{13} ) ^2 \\ 4 + x^2 &=& 13 \\ x^2 &=& 13 -4 \\ x^2 &=& 9 \\ x &=& 3 \\\\ \cot(A) &=& \frac{2}{3} \\ \hline \end{array} \)

Example: 4 and 2

Since there's a 2, you add the 4 two times.

So it'll be like 4*2=8

ez

Subtract 2 from both sides:
(log(2 x^2))/(log(2)) = 1

Multiply both sides by log(2):
log(2 x^2) = log(2)

Cancel logarithms by taking exp of both sides:
2 x^2 = 2

Divide both sides by 2:
x^2 = 1

Take the square root of both sides:
Answer: |x =1      or      x = -1

Q24 am just using CPhill's method of putting it all on a grid.

so

\(gradient=\frac{-105sin75--120cos10}{105cos75-120sin10}\\ gradient=\frac{-105sin75+120cos10}{105cos75-120sin10}\\ gradient=2.64\\ tan\theta=2.64\\ \theta\approx 69.28\\ \)

CPhill did this ths fast way  LOL

Now 69.28 degrees is the angle between the positive x axis and the direction the plane is flying

but the x axis is in the due east direction whereas direction is taken from the due north direction so

the plane is flying on a bearing of   90-69.28 = 20.72 degrees

So just like CPhill found the plane is flying with a bearing of approximately 21 degrees.

thx 

Thank you this helps a lot

it's the sqare root of twelve, so about 3.46. It is irrational, however.

sohcahtoa my friend. Sin is opposite angle/hypotenuse, Cos is adjaecent angle'hypotenuse, and Tan is opposite angle/adjacent angle. Or, if the triangle is a 3,4,5 style, you will instantly have the angle measures of 90, 60, and 30.

well according to the hitchikers guide to the galaxy the answer to life, the universe, and everything else is 42. Hope it helps

for the x and y one y is walk and x is drive, I think

y=3x-15

pi times radius squared

2^-3, then is 2 * (-2), which is -4. Then -4 * (-2), which is 8. Finally 8 * (-2), which is -16

I got this because:   (BTW, + IS A POSITIVE AND -  IS A NEGATIVE)

(+) * (-) = -

(+) * (+) = +

(-) * (+) = -

(-) * (-) = +

Also. 2^-3 is 2 * (-2) * (-2) * (-2)

https://area-of-a-circle.com/

All circle values you may need easy calculator.

Area = (pi)*(radius)^2

Answer these first.

If you rub it, you will experience 'friction' ...

If you want a 'fraction'  , try clicking on the little grey bars in the far right of the display and select "Fractions"