A man travels to Austin, Texas at 40 mph and returns, on the same route, at 60 mph. What is his average speed?
Thanks
WOW HOW DO YOU EVEN DO THAT
im 69 but my dog is 420 his name is Boi
answer: dale needs a bigger pay check
How old r you?
тринадцать
Very.
I'll have to make some assumptions ot get an answer
1 4 weeks in a month (4 weeks vacation per year)
2 40 documents per peson per hour
3 Finsih job in 12 months
800000 documents / 40 doc/hr-person x 40 hr/wk x 4 wk/mo x 12 mo = 10.416 (or 11) people
Only andrew can
46 is the answer
2x + 4y > 12 Subtract 4y from both sides
2x > 12 - 4y Divide both sides by 2
x > 6 - 2y
Agree with discussion.....ONLY when TIME is the same will the average of the two speeds be the simple average of the speeds added together.
40 mph for 1 hr
60 mph for 1 hr average speed is 50 (because you travelled (40 miles + 60 miles)/ (2 hours) )
Is it 1/4 of a mile in 1/32 of an hour? If so, then we have:
(1/4) / (1/32) = 1/4 x 32/1 =32/4 = 8 mph
Tan(x) = 2
arctan(x) = arctan(2)
x = arctan(2) = 63.435 degrees
You are given miles (1/4) and time in hours (1/32) and you want MPH or m/h
(1/4) / (1/32) = 8 mph or 8 m/h
Fair enough!.
You are to be commended for trying owlface.
You are not the only person to make this mistake when averaging speeds. Even the Guiness Book of Records gets it wrong when calculating land speed record attempts!! They take the speeds, calculated seperately, over two distances (there and back) and average them in just the way you did to get an overall average speed. What they get by doing this is not the true average (unless the speeds happen to be the same in both directions)!
13^-14/13^-7 = 1 / (13^14 / 13^7) = 1 / 13^(14 - 7) =1 / 13^7 =1/62,748,517.
8^9*8^5 = 8^(9+5) =8^14 =4,398,046,511,104
2^-1/2^7 = I choose to take it as: 2^(-1) /2^7, if so, then we have:
1 / (2 x 2^7) =1/2^8 =1 / 256
thx alan
Use the fact that a^x/a^y = a^(x-y) and a^x*a^y = a^(x+y)
So 13^-14/13^-7 = 13^(-14 - -7) → 13^(-14 + 7) → 13^-7
8^9*8^5 = 8^(9+5) → 8^14
I'll leave you to try your third one!
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