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Hello! I must admit that I was never good at chemistry so my answer is not the most reliable one. However, the question posted here seems to be pretty simple so I try to answer it. The mass is 0.0012 g, if I am not mistaken.

KrystalBJun 22, 2012

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GuestJun 22, 2012

Jun 21, 2012

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Ignore the last reply my computer glitched.

Anyway, as i was saying, you have to use the formula for Sin in order to get the hypotenuse.
[input]67.2*sin(50)[/input]
Which gives you the length of the hypotenuse, which is what you are looking for.

GuestJun 21, 2012

+3146

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[input]3--2(-4)^2[/input]

adminJun 21, 2012

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Quote:
on a sunny day a tall building casts a shadow that is 67.2 m long. The angle between the sun's rays and the ground is theta = 50 degrees. Determine the height of the building

The base of the triangle is 67.2 m which is opposite to degrees theta which is 50. You are trying to find the hypotenuse of the triangle so you would use the Sin formula.

[input][/input]

GuestJun 21, 2012

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GuestJun 21, 2012

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It's 35.

- Anon.

GuestJun 21, 2012

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Watch out everyone we gotta a bad a*s over here ^^
B***h please you can't troll worth s**t xD

GuestJun 21, 2012

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GuestJun 21, 2012

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Thanks!(: That actually helped a lot!(: but do you mind helping me with the second half of the problem? It's a two part problem and that is only the first half. This is the second half! Thanks SOOOO much if you can help!!!<3(:
[size=150]Round the following to the nearest integer: 10 times the product of answers 3 and 4, all raised to the power of the product of answers 1 and 2.[/size]

-Lizzy(:

GuestJun 21, 2012

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Kitsune123:
1. If COS A=(3/5), Find TAN A (As a fraction)

2. If Sec(x)=(25/7), find SIN(x) (As a fraction)

3. Change 7pi/4 to degrees

4. Find SIN pi/2

For number 1 - Each trig function denotes the ratio of the different sides of a triangle. If you recall, SIN represents the ratio of Opposite/Hypotenuse (The handy acronym SohCahToa, is always useful in remembering). In this equation you want to find TAN, and that is Opposite/Adjacent. Well, we know from the SIN ratio that the 'opposite' side is 3. So far, 3/Adjacent. Well, we can use Pythagorean's Theorem to find the 'adjacent' side (we'll call it 'a'):
3^2 + a^2 = 5^2
9 + a^2 = 25
a^2 = 16
adjacent = 'Plus or Minus' 4
TAN is therefore "plus or minus" 3/4.

For number 2 - The same method is used, so I'll skip a wordy explanation:
Sec(x) = 1/Cos(x), and therefore, is Hypotenuse/Adjacent (You can use the acronym ChoShaCao for the reciprocal identities). Since SIN is Opposite/Hypotenuse, we have Opposite/25. Use Pythagorean's Theorem to find the third side:
7^2 + o^2 = 25^2
49 + o^2 = 625
o^2 = 576
opposite = "plus or minus" 24
SIN is therefore "plus or minus" 24/25.

For number 3 - a simple conversion from PI to degrees is to multiply your problem by 180 degrees/PI. Here you multiply 7 PI/4 by 180 degrees/PI, which in this case is 315 degrees.

For number 4 - You can use a calculator for this one: 1.57
OR
If you have gone over the Unit Circle already, remember that SIN represents the 'y' axis. You can write SIN of PI/2 as Sqrt(2) / 2.

Hope this helps
~Nicholas

GuestJun 21, 2012

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***CORRECTION****

( x ⁴ y ^-3) ^?= y ⁹ / x ¹²

GuestJun 21, 2012

Jun 20, 2012

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GuestJun 20, 2012

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***CORRECTION*** I want to know how to find the midpoint of a segment using points on a graph. point A is at (2,1) and point B is at (8,9). I would also like to know the length.

GuestJun 20, 2012

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That really didn't help much.. but thanks for trying!(:

GuestJun 20, 2012

+3146

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?=0

adminJun 20, 2012

+3146

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rooney72:
If cos x = 0.8 find the value of 16 tan x

cos(x)=0.8
then x equals:
x=acos(0.8)

[input]16*tan( acos(0.8) )[/input]
--------------------------------------
or:
given this formula (any math formulary):
tan( x ) = sqrt( 1 - cos(x)^2 ) / cos( x )

16*tan( x ) = 16*sqrt( 1 - 0.8^2 ) / 0.8
16*sqrt( 1 - 0.8^2 ) / 0.8
16*sqrt( 1 - 0.64 ) / 0.8
16*sqrt( 0.36 ) / 0.8
16*sqrt( 0.36 ) / 0.8
16*0.6 / 0.8
9.6 / 0.8
12

[input]16*sqrt( 1 - 0.8^2 ) / 0.8[/input]

adminJun 20, 2012

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[input]250*92%[/input]
[input]160*8.5%[/input]

adminJun 20, 2012

+3146

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[input]x^3-1=0[/input]

adminJun 20, 2012

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Yerim seni Selma

Mathematik herseyi ölcer bicer ama Aski asla

GuestJun 20, 2012

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admin:
[input](27x)^5/(18y)^5[/input]

yousif khalilJun 20, 2012

+3146

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[input]plot( 1+-3t^2+12t+15, t=0..6 )[/input]
[input]1+-3t^2+12t+15 = 0[/input]

adminJun 20, 2012

+3146

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[input](x+4)*(3x-2=12[/input]

adminJun 20, 2012

+3146

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[input](20*3+8/2)+(80*6/3+8)[/input]

adminJun 20, 2012

Jun 19, 2012

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1/4z-1/8=-3/4x-1/4

GuestJun 19, 2012

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