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square both sides to get

(152i/985)/x = 10^24

x = (152i/985) / 10^24 = 152i/985 x 10^(-24) = .1543147 i  x 10^(-24 )  

  What kind of problem is that???

-12 = -8z + 12    Subtract  12 from both sides of the equation

-24 = -8z            Divide both sides by -8

3 = z

Just use the division sign  (if you look ABOVE the calc display, it will appear as a fraction)

Yes, but it results in a fration, not and integer     2/5  = 0.4  

3x+5  is just that....without more info (like and equal sign and value)  , can't do more than that...

-7  *  1 3/4  =   -7  x  7/4  =  -49/4  = -12 1/4

Let's say you are on the 10:00 train  ....  you will see the train coming form the opposite direction that was launched at 6:00 after you have been traveling approx 30 minutes ...

then t you will see the 7  8  9  10  launches as you travel for  4 1/2 hours  AND you will see the 11 12 13:00 and 14:00 train launches before you arrive at the launching station at 14:30  

That is a total of  9 trains going the opposit direction as you ....

\( \frac{d}{dx}\)cos(x) = - sin(x)

= 800 - .1 x        What else do you want to do with this??

Let's find the inverse of the first one to see if it is the second one (sorry I misread this question initially)

y = (-2x-8)/3      replace x  with y and y with x

x = ( -2y-8)/3     and solve for y

3x+8 = -2y

-4 - 3/2 x = y        this IS the second function ...so they ARE inverses of each other.

2.4 x 10^-7  /  9.6 x 10^-4   =   .25 x 10^(-7- -4) = .25 x 10^-3 - 2.5 x 10^-4

Do 400x75

Let d be number of dimes and q be number of quarters.

d + q = 21

10d + 25q = 405

Multiply the first equation by 10 and subtract from the second equation:

15q = 195.   Hence q = 13

Using this in the first equation we have:  

d + 13 = 21.   Hence d = 8

13 quarters and 8 dimes.

that's a creepy thing to say about mortality

10 km =10,000 meters x 100 cm =1,000,000 cm

1,000,000 / 250 =4,000 number of times the wheel goes around.

the circumference of Terry's wheel is 250 centimeters. Estimate, to 1 significant figure, how many times the wheel goes round when Terry cylces 10 kilometers

\(\begin{array}{|rcll|} \hline && \frac{10\ 000\ m}{2.50\ m} \\\\ &=& 4000 \\\\ &=& 4\cdot 10^3 \\\\ \hline \end{array} \)

The wheel goes round 4000 times.

 
  _6_X (1+2)= If it were written like this, you wouldn't multiply 2 x 3, but[ 6 x 3] / 2 =9
    2

(To Guest)

You have to use B.I.D.M.A.S and so add the 2 and 1 in the bracket first to get 3. Then you do the division of 6 by 2 to get 3. You sould get 3(3) and due to the brackets you times the two, as in the 3 and 3, to get 9.

composition of f(x)=2x^2 and g(x) = x+3 (fog)(x)=?

\(\begin{array}{|rcll|} \hline f(x)=2x^2 \\ g(x)= x+3 \\ && (f\circ g)(x) \\ &=&f\left(\small{g(x)}\right) \\ &=&f\left(\small{x+3}\right) \\ &=& 2\cdot (x+3)^2 \\ &=& 2\cdot (x^2+6x+9) \\ &=& 2x^2+12x+18 \\ \hline \end{array} \)

(fog)(x)=2(x+3)²
=2(x+3)(x+3)

=2x²+12x+18

Why not 6/2(1+2)=1?

(different Guest)

I liked this question - it kind of looked scary but it was really rather simple :))

And

Chris, it is dinner time and I would rather have a sushi train than a train of thought :))

Here I have done another, I used the same method but this time it did take 3 reflections.

This is why it is different from the others.

FFor the first two you could get from the forst shape to the second shap using translation and rotation.  

The corresponding points A,b,c etc were both a clockwise direction.

With the example below, a reflection was also involved,  in the initial pentagon on the right the points go clockwise but the congruent shape on the left (the brown one) the letters go in a anticlockwise direction.