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Well, it can ONLY be boysenberries.

no worries, its modulo arithmetics

CPhill: Agreed. My computer used iteration and interpolation.

true

Landon opened a savings account with a deposit of $3,786.45. Nine years later, the balance in the account is $5,135.29. If the interest rate is 3.4%, how often does the interest compound?

5135.29 = 3786.45 (1 + .034/ n ) ^[9n]    

I think this might be difficult to solve, algebraically  [ but, I'm not sure......!!!! ]

WolframAlpha shows the answer to be n  = 4   [ quarterly compounding]

Proof :  3786.45 (1 + .034/ 4 ) ^[9*4]  ≈  5135.29  

FV = PV [1 + R]^N

5,135.29 =3,786.45 [1 + 0.034/N]^N, solve for N

N = 36

36/9 =4 number of componding periods per year, or quarterly compound.

$766 x .2043/12 = $13.04 Monthly interest

2x  -  6

Future population = Current population [1 + (-0.061)]^Number of years.

FP = 435,410 x [0.939]^8

FP = 435,410 x 0.6044

FP =~~263,162 people.

P = 435410 ( 1 − .061)^8   ≈  263162

What is the equation of the line with an x-intercept of -1 and a y-intercept of 2?

y = 2x - 2

y = - 2x + 2

y = 2x + 2

y = 2x + 2

Simply imagine the graphic.

   !

It was solved yesterday! Did you foget about it? Here it is:

PV = FV / [ 1 + R]^N, PV=present value, FV=Future value, R=Interest rate, N=Number of periods.

PV = 1,437.34 / [1 + 0.029/4]^(11*4)

PV =1,437.34 / [ 1.0075]^44

PV =1,437.34 / 1.374169

PV =$1,045.97 What Joshua deposited 11 years ago.

2+3 = 3+2

We have  (−1, 0)  and (0,2)  .....the slope is  [ 2 − 0 ] / [ 0 − (−1)  ]  =  2 / 1   = 2

And the y  intercept = 2

So......y = 2x + 2   is correct

y= mx + b   is the equation of a line    when x= 0 you get y intercept   when y= 0 you get x intercept

y = m(0) + b    b= 2

0 = m(-1) + 2       m= 2

y= 2x+2 

Jaysus

Here is 28: 1 + [sqrt(9)^(9 - 6)] =1 + 3^3 =28

Super Bowl ???   .....Me.!!!   Me.....!!!

[ABD ] =  "Anybody But Dallas "

Permute any 5 letters chosen from 7   =   P (7,5)   = 2520

f(x)=5^2+7, f(x) =8-3x

\(f(x)=5^2+7=32\)

                                           [ Equilibrium

\(f(x)=8-3x\)

\(32=8- {\color{red}3} x\)                   [+3x; -32 on both sides

\({\color{red}3}x=8-32=-24\)    [ / 3   on both sides

\(x=-8\)  

Greeting Omi67  !

Since you are an investor and NOT a student, I'm not going to explain to you how the bond price is calculated, since there are at least 4 different formulas used to arrive at the price of this bond. Part of the reason, is that the settlement date of Jan. 6, 2017 does not coincide with the coupon payments dates of March 15 and Sept.15 of every year. Unfortunately, that fact complicates things.

I will be using actual number of days between dates, instead of some practices of using 360 and 30 days.

So, based on all the above, the price of your bond should be:

$113.990 + $1.249 accrued interest =$115.239. Accrued interest is from Jan. 6, 2017 to the next coupon date of Mar. 15, 2017.

The quote from your broker should agree with this calculation. Good luck to you.

lim          sin(5x) / x             multiply top/bottom by 5

x → 0

lim          (5) sin(5x) / (5x)      abd we can write            

x → 0

 5 *   lim          sin(5x) /  (5x)            

        x → 0   

5 *    [ 1   ]    =

5 

See the graph here : https://www.desmos.com/calculator/wmfmgsmfrg 

dallas is bae

f(x)=5^2+7, f(x) =8-3x

5^2 + 7 =  8 - 3x

       32 = 8-2x     |-8

       24 = -2x       | : (-2)  

         x = -12