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ya what he said

I called you a "smart cookie" Max that does not mean you are "The Smartest Cookie in the World".   :)

I have created a monster.   LOL  :)

Yea this place used to be hilarious.  I used to spend all night laughing - well often anyway. :)

It is still a good place to be but it is not quite the same. :)

PS   You can call yourself  "the smartest cookie in the world"  if you want to.   LOL   :))

sgn(2.5)

= \(\dfrac{2.5}{|2.5|}\\ = 1\)

               -1 when x< 0

sgn(x) = undefined when x = 0

              1 when x > 0

https://www.desmos.com/calculator/hnpqmpeny5 

A graph of sgn(x).

If you didn't ask this question I wouldn't do research about sgn(x)....... Anyways, Thank you!!

~The smartest cookie in the world

So many dialogues.......

I didn't imagine there were so much funny dialogues in the historical posts.

Maybe I will start searching some of these kind of historical posts! :D

~The smartest cookie in the world

I see.

I am glad that you explained that Ginger, I am not good at 'subtle'  LOL      

Thanks Ginger.

I forgot how long AND how funny those posts were.

I was laughing out loud all over again!

We used to have a LOT of fun here.

Nauseating proclaiming himself

Royal SOB   (superintendent of building)    

And the way Rosala used to tease Zegroes by calling him Zeg-rose

Those two were hilarious together.

Zegroes visitied me earlier today (left a message)

I always love hearing from him and Rosala.

I like hearing from all the early characters - it is really good hearing what they are up too. :)

I wonder what Eloise is up too ??  Or Puzzled, whatever became of her ?

There have been so many good kids through here :)

Now I am getting nostalgic :)

Thanks so much Ginger for providing these wnderful reminders :D       

In the post above mine, Sir CPhill typed the “Roman Zero” just as Morgan Tud described it. I reasoned Sir CPhill found it in the bolder of Sisyphus and chose a subtle path to announce it.

y + x = 12

y = 12 - x

~The smartest cookie in the world

Who is Emily LOL

Btw it IS 2 to the power 4, not -4

y + x = 12

y = 12 - x

~The smartest cookie in the world

Sorry,

y+x=12

solve for y=

Here's a start.

This is Classic Zegroes and Rosala with guest star Rose98 (a.k.a. “Rose not La”)  

Only one equation but 2 variables. Cannot be solved.

~The smartest cookie in the world

Watch your language...... Respect other languages.

~The smartest cookie in the world

1. Press the '\(\sum\)LaTeX' button.

2. Type \dfrac{a}{b} and press OK

3. \(\dfrac{a}{b} \) will appear.

~The smartest cookie in the world

\(1\dfrac{1}{3}\div \dfrac{2}{3}\\ = \dfrac{4}{3}\div \dfrac{2}{3}\\ = 4 \div 2\\ = 2\)

Round 0.52173913043 to a whole number.

Round it up at the tenths.

= 1.

~The smartest cookie in the world

Because Maths is really so fun!!!!!

~ The smartest cookie in the world

wat the h**l!!!

er du en god lommeregner. tak

Hej! Fortæl os alle, hvor du har brug for hjælp. Vi er glade for at hjælpe. 

hilsen asinus :- )    !

cos

\(x²-3x-10=0\)

I could see that x=5 is a root for this equation (if we replace x by 5 we get 0) 

That means I can factorize this equation like that: 

\(x²-3x-10 = (x-5)(x+2)\)

\(\Rightarrow (x-5)(x+2)=0\)

\(x-5=0 \Rightarrow x=5\)or

\(x+2=0 \Rightarrow x=-2\)

Learn to write your formula accurately as follows:

Instead of this that you wrote down:

2400(1+0.0434)24

It should look like this:

2,400[1 + 0.43/4]^(6*4)

2,400[1 + 0.01075]^24

2,400 x 1.01075^24

2,400 x 1.292558

=$3,102.14

Emily, isn't it 2 left to the power -4? You and Max made 2 left to the power 4 

\(\sqrt[3]{{(2{n}^{0})}^{-4}.2.{m}^{2}.{n}^{4}.{m}^{-1}.{n}^{3}\over {m}^{-4}.{n}^{4}}\)

\(=\sqrt[3]{{2}^{-4}.2.{m}^{2}.{m}^{4}.{n}^{4}.{m}^{-1}.{n}^{3}.{n}^{-4}}\)

\(=\sqrt[3]{{2}^{-3}.{m}^{2}.{m}^{4}.{m}^{-1}{n}^{4}.{n}^{3}.{n}^{-4}}\)

\(= \sqrt[3]{{2}^{-3}.{m}^{5}.{n}^{3}}\)

\(= \sqrt[3]{{n}^{3}\over{2}^{3}}*\sqrt[3]{{m}^{5}}\)

\(= \frac{n}{3}.{m}^{\frac{5}{3}}\)