Before it bounces it travels 30 m
betweent the first and second bounce it goe UP 15 m and down 15m then the second bounce occurs.....etc
We are not counting the distance it travels AFTER the 9th bounce (per the question)
30+ (2)(30 x .5) + (2) 30 x .5 x .5 +(2) 30 x .5x.5x.5 .....= 30+ 60 (.5 + .5x.5 + .5x.5x.5....) =30+ 60\(\sum_{1}^{8}\) .5^n =
30 +60(.99609) = 89.765 m
Can anyone verify this????
Thanx