All Answers 356050 Answers

7t + 10t =68

t = 4 hours.

-1/3 - x = x - 9   add  x, 9 to both sides

-1/3 + 9  = 2x

-1/3 + 27/3  = 2x

26 / 3  =  2 x       divide both sides by 2

13 / 3  = x

This is a calculator site.  Use it!

how do i get the exact value of cos(13pi/3)

\(cos\frac{13\pi}{3}\\ =cos(\frac{12\pi}{3}+\frac{\pi}{3})\\ =cos(4\pi+\frac{\pi}{3})\\ =cos(2\pi+2\pi+\frac{\pi}{3})\\ =cos(\frac{\pi}{3})\\ =cos60^\circ\)

Now you can read cos 60 straight off this triangle :)

4n + 16  =  4 (n+4)    so

4 (n+4)/(n+4)   = 4

λ =           [ 6.63x10^-34 m^2 kg/s ] / [(1.67x10^-27kg)(600 m/s)] =

[6.63] / 1.67 * 600] * [10^-34] / [10^-27] m  =

 ( [ 0.0066167664670659] * 10^27 / 10^34) m  =

[ 0.0066167664670659] * 10^-7   m 

 6.6167664670659 * 10^-10   m

13 pi /3 is equal to  4 1/3  pi    which is the same as  pi/3    (every 2 pi is a complete circle and gets you back to your starting point) 

cos pi/3  = cos 60 = 1/2

First let's do a dimensional analysis to make sure you have the correct numbers

  Lambda =  m^2 kg /s   / ( kg-m /s)     results in an answer     m^2-kg/s  x  s/kg-m  =  m   so your answer will be in meters

Then just do the math with your numbers

= .006616766 x 10 ^(-34 +27)  = .0066167 x 10^-7   m  =  6.6167 x 10^(-10)  m

The product of the first three is equal to the last three_____________         what?   Added?

Here is a list of the first 168 primes....maybe you can answer your own question....

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997

beacause

Net force on 1/3 due to the other two is found as follows. 
11 is pushed to the left by 1/3 and pulled to the right. by 12 
Taking right as positive 
F = kq1 (q3 (d1 + d2) ^2 - q2 /d1^2} 
F = 9e9* 6.24e-6* 1 e-6 {(2.06/ (0.05) ^2 – (1.39 /0.03^2)} 
F = - 40. 46 N 

-11.3 repeating

21 (ya stupid!!!!!!!!!)   JK (19)

Of course it is. Suppose the only given condition is that the function has a zero at the origin. Then the function can be x or x^2 or sin(x) or tan(x) or 862*x^17. (taken from yahoo answers.)

.004864864

use a calculator dude

To solve this you are given   y= 2x     Substitiute this value of y in to the second equation...

     x + 2x = 12

    3x = 12

      x = 4         Now that you know x....you can substitute this into any of the equations to find y

        the simplest is  y = 2x    so y = 2(4) = 8        so x,y =  4,8

The answer is 20/27

19. inauthentic and unamusing.

x+2x=12

3x=12

x=4

Y-is independent and X-is dependant. So your right!!1 WAY TO GO!!!

Distance =  sqrt(  ( y1-y2)^2 + (x1-x2)^2) = 

sqrt (-3-(-5))^2 + ( 2-5)^2 ) = sqrt ( 4 + 9) = sqrt 13 = 3.61  

When s = 35   F(s) = 105.88

when s = 50    F(s)= 192.5

F(50) - F(35) = 86.62     this is the difference between  stopping distance between 50 and 35 mph

so the average linear approximation would be    86.62 ft/ (50-35)mph = 5.775 ft / mph   

  In other words   each 1 mph increase in speed  increases stopping distance by 5.775 ft   (linear APPROXIMATON)