All Answers 356076 Answers

1)    1in/2ft  =  9in/x ft       x =  9 / (1/2) = 18 ft

2)

3)    1 cm / 13 km  =  x cm/130cm     x = 1/13 x 130 = 10 cm

4)

I'll let you work on 2 and 4

Do you have the pH ?

4.181818181818181... as a fraction

\(\begin{array}{|lrcll|} \hline (1) & 100 \times 4.\overline{18} &=& 418.\overline{18} \\ (2) & 1\times 4.\overline{18} &=& 4.\overline{18} \\ \hline (1)-(2) & 100 \times 4.\overline{18} - 1\times 4.\overline{18} &=& 418.\overline{18} - 4.\overline{18} \\ & 99\times 4.\overline{18} &=& 414 \\ & 4.\overline{18} &=& \frac{414}{99} \\ \hline \end{array} \)

How do i find the surface area?

\(\begin{array}{|rcll|} \hline V(s) &=& \left( 0.4547\cdot s^{\frac12} \right)^3 \quad & | \quad \text{cube root both sides} \\ \sqrt[3]{V(s)} &=& 0.4547\cdot s^{\frac12} \quad & | \quad : 0.4547 \\ \frac{\sqrt[3]{V(s)}}{0.4547} &=& s^{\frac12} \quad & | \quad \text{square both sides} \\ \left( \frac{\sqrt[3]{V(s)}}{0.4547} \right)^2 &=& s^{\frac22} \\ \left( \frac{\sqrt[3]{V(s)}}{0.4547} \right)^2 &=& s^1 \\ \left( \frac{\sqrt[3]{V(s)}}{0.4547} \right)^2 &=& s \\ \mathbf{s} & \mathbf{=} & \mathbf{\left( \frac{\sqrt[3]{V(s)}}{0.4547} \right)^2} \\ \hline \end{array} \)

\(\begin{array}{|rcll|} \hline s &=& \left( \frac{\sqrt[3]{V(s)}}{0.4547} \right)^2 \quad & | \quad V(s) = 2500\ m^3 \qquad s \text{ in } m^2\\ s &=& \left( \frac{\sqrt[3]{2500\ m^3}}{0.4547} \right)^2 \\ s &=& \left( \frac{13.5720880830\ m}{0.4547} \right)^2 \\ s &=& ( 29.8484453111 \ m )^2 \\ s &=& 890.929687492\ m^2 \\ \mathbf{s} & \mathbf{\approx} & \mathbf{ 890.93\ m^2 } \\ \hline \end{array} \)

How do i find the height?

\(\begin{array}{|rcll|} \hline h &=& 62\cdot \sqrt[3]{t} + 76 \quad & | \quad -76 \\ h - 76 &=& 62\cdot \sqrt[3]{t} \quad & | \quad :62 \\ \frac{h - 76}{62} &=& \sqrt[3]{t} \\ \frac{h - 76}{62} &=& t^{\frac13} \quad & | \quad \text{cube both sides} \\ \left({\frac{h - 76}{62}} \right)^3 &=& t^{\frac33} \\ \left({\frac{h - 76}{62}} \right)^3 &=& t^1 \\ \left({\frac{h - 76}{62}} \right)^3 &=& t \\ \mathbf{t} & \mathbf{=} & \mathbf{ \left({\frac{h - 76}{62}} \right)^3 } \\ \hline \end{array}\)

\(\begin{array}{|rcll|} \hline t &=& \left({\frac{h - 76}{62}} \right)^3\quad & | \quad h = 231\ cm \qquad t \text{ in years}\\ t &=& \left({\frac{231 - 76}{62}}\right)^3 \\ t &=& \left({\frac{155}{62}}\right)^3 \\ t &=& {2.5}^3 \\ \mathbf{t} & \mathbf{=} & \mathbf{15.625 \text{ years}} \\ \hline \end{array}\)

Hello

I've forgotten the six feet.
So

\(h=54ft+6ft-254ft\times tan 12^0 = 60ft-53.989ft=6.01063ft\)

\(The \ other \ "building" is \ 6.0106\ ft \ high. \)

\( Maybe \ a \ garden \ holiday.\)

!

It may be 4 ( ͡° ͜ʖ ͡°)

Order of operations. Do 16 / 2 first then multiply your answer of that by 9 to get a final answer.

got it nvm

click the 1/x butten

Yes

Talk to a Tax Accountant.

answer: 

556097555030406243425281206034739614028663646586234884602336828137140161532770156015566255663574728144172916102325775783032355137312770524981592308468377944919354888224752133719929721076396532828999535598508502213805038

@CPhill: I do not think that your solution to part b adequately explains what "something" is in the equation provided to us. You seem to have put down the same pattern, but not what the pattern is equal to. Please make that clearer. Thanks!

It will be $1,207.98

Answer:

1641

i must say that i do not like him but i will give him a chance.

count the number of numbers and the denominator will be that many zeros

.7357 = 7357/10,000

(has 4 places=4 zeros)

Hi, how's your day?

An outlier is a section of data that is separated from the rest. 

Okay, so to subtract fractions, the numbers need to have common denominators. So you'd have to make 6 have a denominator of 10.

And how would we do this? Well, since six is a whole number, it's also 6/1. To make this fraction have a denominator of 10, we multiply both the numerator and denominator by ten, thus getting 60/10.

Next, you make 2 9/10 into an improper fraction. You should times two by ten, then add what you get to the numerator, thus getting an improper fraction of 29/10.

And then we just subract the numerators and keep the denominators, getting 31/10. To change this into a mixed number, just figure out how many tens can go into 31-- essentially, 31 divided by 10. You would get 3 remainder 1, so your mixed number is 3 1/10.

your mom

Who knows