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z^2/z  =  z^2/z^1  = z^2 (z^(-1)) = z^(2-1) = z^1 = z     Ta Da!!

Not sure EXACTLY what your parmeters are in your question, but look at this scenario:

x^2+10x+ 20     first  student increases the x coefficient by ONE

x^2 + 11x + 20    the next 10 students DECREASE the constant by ONE:

x^2 + 11x + 10      the next 9 students INCREASE the x coefficient by ONE

x^2 + 20x + 10         The end

the RED intermediate quadratic is factorable to  (x+1)(x+10)     two integer roots of -1 and -10  

Is THAT what you meant??? 

75 grams can be UP to 75.4   or as LOW as 74.5   and still be rounded to 75 gm

120                      UP to 120.4          LOW as 119.5                                      120

120.4  - 74.5 = max diff = 45.9

MIN diff = 119.5 - 75.4 =  44.1 gm

1.  I'll let you compose a sentence...but HERE is one: (LOL)
  According to www.whitehouse.gov, the government had about $2.1 trillion in receipts and $2.8 trillion in outlays for 2013.

2 Ratio  2.8 tril / 2.1 tril =  x / 53143      x = how much YOU would spend

      Multiply both sides by 53143     2.8/2.1 x 53143 = x =  $ 70,857

3 The deficit is how much the budget is short THIS year that the government will BORROW and spend this year.  This DEFICIT will be added to the cumulative  DEBT which is summed over the years of deficits.

Current US DEBT (Money we OWE )  $ 20.1 TRILLION  20,100,000,000,000.    Crazy.

If I understand your question correctly, the two points are:

(M,-44) and (P,[2-1])

That is:

(M,-44) and (P,1)

All you need to do is put this info into the distance formula.

d=\(\sqrt{(M-P)^{2}+(-44-1)^{2}}\)

d=\(\sqrt{(M - P)^{2}+(-45)^{2}}\)

d= \(\sqrt{(M - P)^{2}+2025}\)

17%

51 / 300 = .17  =  17 / 100  =  17%

What are the coordinates of M ....????.....you only listed one......

by 1, sorry about that. Can you please help me...please explain in detail.

4, 4/3, 4/9, 4/27, 4/81......etc.
Common ratio = 1/3
Sum(5) =5 79/81
Sum of the squares of the terms converge to=18
Sum of the terms converge to =6

Thanks, Alan......!!!!

y = -x + 6

y = -6x – 9     set both equations equal

 -x + 6  = -6x – 9      add 9, x  to both sides

15 = - 5x           divide both sides by - 5

-3  = x       sub into either equation to find y

y = - [ -3] + 6   = 9

So  {x , y}  =  {-3, 9 }

4^3 - 5^2

= 64 - 25

= 39

x=-3, y=9

5(1+2)^2-4(3-1)^3-6(2+3)^4

= 5(3)^2 - 4(2)^3 - 6(5)^4

=5(9) - 4(8) - 6(625)

= 45 - 32 - 3750

= -3737

Solve for y:
-y^2 + 9 y - 6 = 3

Multiply both sides by -1:
y^2 - 9 y + 6 = -3

Subtract 6 from both sides:
y^2 - 9 y = -9

Add 81/4 to both sides:
y^2 - 9 y + 81/4 = 45/4

Write the left hand side as a square:
(y - 9/2)^2 = 45/4

Take the square root of both sides:
y - 9/2 = (3 sqrt(5))/2 or y - 9/2 = -(3 sqrt(5))/2

Add 9/2 to both sides:
y = 9/2 + (3 sqrt(5))/2 or y - 9/2 = -(3 sqrt(5))/2

Add 9/2 to both sides:
Answer: |y = 9/2 + (3 sqrt(5))/2               or                       y = 9/2 - (3 sqrt(5))/2

No, this is Patrick.

Go eat some more memes.

Learn to use the calculator here. Try it and see what you get.

5,040 / [1.2.3.4.5.6]=7

x=7, so that:

7! = 5,040.

Total number of students=S
Number of girls =G
Number of Boys =G+124
G+G+124 = S
11/20S =G+124, solve for G, S
G=558 - Number of girls.
S =1,240 - Total number of students
1,240 - 558 =682 - Number of boys.

2 to what equals 256

Volume of a cylinder = pi*(diameter/2)^2*height

Volume = pi*(225*2214/2)^2*2214  ft^3

I'll leave you to crunch the numbers!

.

"at a school number of boys:number of girls=11:9

there are 124 more boys than girls

work out the total number of students at the school"

b/g = 11/9    so  b = 11g/9

g + 124 = b     so  g + 124 = 11g/9   Multiply both sides by 9

9g + 9*124 = 11g     subtract 9g from both sides

9*124 = 2g    divide both sides by 2

g = 9*124/2   or g = 9*62   so  g = 558

Hence b = 558+124   or  b = 682

Total students = 558 + 682 = 1240

.

Hmm!

Let W = width, L = length, H = height

V = WLH                 A = WL + 2HL + 2WH

(i) W = L = H

V = W³            A = 5W² 

(ii)  L = 2^1/2W     H = 2^-1/2W

V = W* 2^1/2W*2^-1/2W    so   V = W³ still.

A = W*2^1/2W + 2* 2^-1/2W*2^1/2W + 2*W*2^-1/2W    so  A = (2^1/2 + 2 + 2^1/2)W²

A = 2(1 + 2^1/2)W²     or  A ≈ 4.828W²  i.e. a slightly smaller area for the same volume!