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Nice, hectictar.....!!!!

I didn't do it like that Chris,

I just said there are 5 books, any of them could be in the first position so the probability that any in particular one is first is 1 in 5.

Easy peazy :))

OK......no prob......

Total possible committees   =  C(9,4)  = 126

Those possible with 3 technical people  =  C(5,3)*C(4,1)  = 40

Those possible with 4 technical people  =  C(5,4)  = 5

P[ at least three technical persons ]  =  [ 40 + 5] / 126 = 

45 / 126  =  15/42  = 5 / 14 ≈ .357  ≈  35.7%

The height of the building over the height of the man equals the length of the building's shadow over the length of the man's shadow.

h/1.8 = 26.4/3

h = 15.84

The height of the building is 15.84 meters.

The tangent of the angle of elevation to the sun is 15.84/26.4

tan a = 15.84/26.4

a = arctan 0.6

The angle of elevation to the sun is approximately 30.964 degrees.

Thank you CPhill! 

The possible permuted sets of choosing 2 b***s from 7  = P(7,2)  = 42

But the only ones we are interested in are  {2,6} or {6,2}

So.....

2 / 42  =  1 / 21   ≈ 4.76%

Oh there are a couple of Latex threads, they are in our sticky topics ... so everyone can find them easily  :)

Added to our LaTex thread here:

How to put different types of brackets around matrices - or no brackets at all !

http://web2.0calc.com/questions/test-2#r2

To see Melody's answer....

The possible number of  sets consist of the possible permutes of choosing any 3 of the 5 books  =  P(5,3)  = 60

We want to choose the sets    {3, a, b}    where a,b  are the possible permutes  of choosing two of the other 4 books  = P(4,2)  = 12

So....12 / 60   = 1 / 5  .

Mmm

I worked this our from here

.25555.....=

[25 - 2 ] / 90  =  23 / 90

one in five

\(\frac{1}{5}\)

If six coins are flipped, what is the probability of getting exactly two tails?

\(P(2 tails)=\binom{6}{2}0.5^6=15*\frac{1}{64}=\frac{15}{64} \)

......................

3 examples of Quantitive reasoning that is used in real life? 

5 sqrt(x-8) = 10   divide both sides by 5

sqrt(x-8) = 2      square both sides

x-8 = 4      add 8 to both sides

x= 12

Agreed,,,I guess the question needs to specify what limits of rounding are  ( you could go to 75.499999999999999...) and what practical weight measurements are available in manufacturing and packaging !    I felt 100mg was 'practical'    LOL

So you're saying write this equation and try to figure out what f is?

\(\frac{x}{0}=xf\)

You can rewrite that like:

\(x\frac{1}{0}=xf\)

So f is just going to be 1/0, and x times that is also undefined.

Just testing how to write a number over a number without a fraction line in LaTeX, and I doubt that question can be solved.

10+395+2.5=407.5

407.5???

I worked on this some and I think it is impossible to go from the beginning equation to the final equation without writing down an equation with integer roots at least once. At some point the constant, "c", will be exactly one greater than the linear coefficient, "b". When c is one greater than b,  there will be integer roots.

EP    I think the bottom one should go up to  75.4999999 = 75.5

Rice is sold in 75-gram packs and 120-gram packs.

74.5  to  75.5                               119.5 to 120.5

lowest possible difference = 119.5 - 75.5 = 120-75-1 = 44g

On three 150-point geography tests, you earned grades of 88%, 94%, and 90%. The final test is worth 250 points. What percent do you need on the final to earn 93% of the total points on all tests?