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the answer is 2 over 4. Why? Because both numbers are equivalents of 2, so divide each by 2 and you'll get the answer!

Hi, there's nothig much I can do for you, but I'm sure your parents don't hate you. I can feel the same way sometimes, but no matter what, just know your parents always love you and are just trying to ensure the best for you. Hope tjis helps!

I don't know the answer, but for imformational videos that would help alot go to Youtube.com and search How to find the area of cylinders. there should be a few videos, just pick one and go!

Hope this helps!!

I hope that helped!

Find the following limit:
lim_(x->0) (3^x - 10^x)/x

Applying l'Hôpital's rule, we get that
lim_(x->0) (3^x - 10^x)/x | = | lim_(x->0) ( d/( dx)(3^x - 10^x))/(( dx)/( dx))
 | = | lim_(x->0) (3^x log(3) - 10^x log(10))/1
 | = | lim_(x->0) (3^x log(3) - 10^x log(10))
lim_(x->0) (log(3) 3^x - log(10) 10^x)

lim_(x->0) (3^x log(3) - 10^x log(10)) = 3^0 log(3) - 10^0 log(10) = -log(10/3):
Answer: |-ln(10/3) =- 1.2039728....

Thanks! I beleive that is correct!

No worries! I just wanted to quiz someone! :)

1) In compounding you get "interest on interest". Example: $1,000 that earns interest @ 6% compounded annually. So, for the first year you get: 6/100 x 1,000 =$60. But in the second year you get: another $60 + $60 of year 1 + interest on this last amount @ 6%, which comes to $3.60, for a total of: $60+$60+$3.60=$123.60 for 2 years.

2) In simple interest you just get $60 year after year after year!. So, in 2 years you get $60 x 2=$120.

Now, for 2 years there doesn't seem to be that much difference. But if you went for 20 years, then the difference between the two would as follows:

a) - In 20 years using compounded interest, you would have:$2,207.14 in interest ONLY.

b) - In 20 years using simple interest, you would have: $60 x 20 =$1,200 in interest ONLY.

Now, you can see the power of componding interest vs simple interest.

limit as x approaches 0 for (3^x-10^x)/x

The numerator and the denominator both tend to 0 so I am going to try l'hopital's rule

mmm 

\(let\;\;\\ t=3^x\\ ln_3t=x\\ x=\frac{lnt}{ln3}\\ \frac{dx}{dt}=\frac{1}{tln3}\\ \frac{dt}{dx}=tln3\\ \frac{dt}{dx}=3^xln3\\ \)

Using the same method

\(\frac{d}{dx}(10^x)=10^xln10\)

\(\displaystyle\lim_{x\rightarrow 0}\;\;\frac{3^x-10^x}{x}\\ =\displaystyle\lim_{x\rightarrow 0}\;\;\frac{3^xln3-10^xln10}{1}\\ =\displaystyle\lim_{x\rightarrow 0}\;\;3^xln3-10^xln10\\ =ln3-ln10\\~\\ =ln(0.3)\\~\\ \approx -1.204 \)

Here is the graph

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3233333.3 repeating (You can paste the equation into the super handy calculator and get the same thing.)

45% x 120 is the same thing as saying (.45 x 120)

54 should be your final awnser.

Not sure       -1.2039????      (L'Hopital rule)

Assuming that all squares are equal size, 18 of 32 are shaded creating the fraction

of 18/32 (18 over 32)

18/32 simplified would be 9/16

Just use the calculator to find:

1573(1.02)^10 = 1917.4782226517529659

I just went to WolframAlpha :

y+5=9(x+6)

First to simplify the right side I would do distrubutive property

y + 5 = 9x+54

subtract 5 from both sides

y = 9x+49

being two different variables this is as far as the simplification goes.

Hello Max: This is the huge "mess" I got when I plugged into Wolfram/Alpha!!!.

http://www.wolframalpha.com/input/?i=(x)%2B(y)%2B(z)%2B1%3D16(xyz),+(xy)%5E4%2B(yz)%5E4%2B(xz)%5E4%2B81%3D16*%5B(x)%2B(y)%2B(z)%5D,+solve+for+x,y,z

H  price =  8 + 2.25 x     where x = number of tickets

P              50 + 1.25 x   

And you wnat to know when they are equal:

8+2.25x = 50 + 1.25 x    Subtract 8 from both sides

2.25x = 42 + 1.25x          Subtract 1.25 x from both sides

x = 42   = number of tickets to equal price  at both carnivals

If the calculator is broken.......

567.893 divided by 3.9 = 145.6135897

6 would go on the x axis (the left and right line) so go six to the right then for 8 the y axis (up and down line) from that six you would move up 8 spaces giving you the point of (6,8)

Is the calculator on the home page broken??

copy an paste it ino the calc on the home page.

(x+4)^4 is the same as (x+4)(x+4)(x+4)(x+4)

which can be further simplified to 4x+256

;)

Area_cube  =   6 * [side length ]^2